PLEASE HELP MULTIPLE QUESTIONS QUICKLY WILL FAN AND GIVE MEDAL Solve the equation on the interval 0≤θ<2π. sin(3θ)=−1

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PLEASE HELP MULTIPLE QUESTIONS QUICKLY WILL FAN AND GIVE MEDAL Solve the equation on the interval 0≤θ<2π. sin(3θ)=−1

Mathematics
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Take the inverse sin of both sides and then solve for θ.
\[\text{ Let } x=3 \theta \text{ so } \theta=\frac{x}{3} \\ \text{ we want to solve } \sin(x)=-1 \text{ on the interval } 0 \le \frac{x}{3} <2 \pi\]

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Other answers:

Guys I've been sick so I missed a lot of school and this homework is due at 12 and I'm really struggling so please explain it so I can understand it quickly
do you know how to solve sin(x)=-1 on 0 <=x<6pi?
if not do you know how to solve sin(x)=-1 on 0<=x<2pi?
no ive been absent for a while I'm trying to see if someone can work it out step by step so I can understand whats going on
https://www.mathsisfun.com/geometry/images/circle-unit-radians.gif can you tell me when the y coordinate is -1 here?
For example If I asked you to look at that chart and tell you to tell me when the y-coordinate is 1, the answer I would be looking for is pi/2. Which means sin(pi/2)=1
at 3pi/2
yes
sin(x)=-1 when x=3pi/2 if we were only looking at 0<=x<2pi but we also need to find the roots in 2pi<=x<4pi and the one in 4pi<=x<6pi so that means there are two more roots to be found guess what we can just find these by adding 2pi to our already found root and then 2pi again x=3pi/2 x=3pi/2+2pi x=3pi/2+2pi+2pi or 3pi/2+4pi now we are not done remember we let x=3 theta
and what we actually want to solve for is theta not x
so replace x with 3 theta
and solve the linear equations
solve all three linear equations below: \[3 \theta=\frac{3 \pi}{2} \\ 3 \theta=\frac{3\pi}{2}+2\pi \\ 3 \theta=\frac{3\pi}{2}+4\pi\]
did you have any questions ?
I think I might have a simpler solution. It also requires less steps. First, let's get rid of the 3θ and substitute it with x. Easy enough, right? \[\sin(x)=-1\] Now let's think of the unit circle here. What angle gives us -1 when we take the sign of it? 3pi/2 right? Perfect! \[x=\frac{ 3\pi }{ 2 }\] We can check this by taking the sign of it.\[\sin(x)=\sin(\frac{ 3\pi }{ 2 })=-1\] Look at that. Now that we have x, substitue that 3θ back in there. \[3\theta=\frac{ 3\pi }{ 2 }\] Therefore\[\theta=\frac{ 3\pi }{ 6 } \in [0, 2\pi)\]
sin* not sign
well you will have 3 solutions not just one
Ah yes, but that can be done by cumulatively adding 2pi before dividing by 3. One extra step.

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