CountryBoy15
  • CountryBoy15
need help please help Name and describe the phase change that occurs when solid carbon dioxide (dry ice) is placed in an open container at room temperature.
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Photon336
  • Photon336
@CountryBoy15 Look at this |dw:1444191107393:dw|
Photon336
  • Photon336
well it's called sublimation solid goes directly to gas without going to the liquid phase \[(Solid) -> (Gas) \]
Photon336
  • Photon336
the solid ice goes directly to the gas phase without passing through the liquid phase

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

NotTim
  • NotTim
Maybe ask this as a new question, countryboy15
Photon336
  • Photon336
\[pV = nRT \] the temperature and number of particles (moles n) are constant so \[p_{1}V_{1} = p_{2}V_{2}\]
Photon336
  • Photon336
We are looking for V_{2} so we isolate \[V_{2} = \frac{ P_{1}V_{1} }{ P_{2}}\]
Photon336
  • Photon336
just plug in the numbers \[1 atm = 101.3kpA \] \[\frac{ 270 }{ 101.3} = 2.66atm = P_{1}\] \[\frac{ 540 }{ 101.3} =5.33 atm = P_{2}\] \[V_{1} = 1 L \]
Photon336
  • Photon336
Plug the numbers above into this equation \[\frac{ P_{1}V_1 }{ P_{2} } = V_{2}\]
Photon336
  • Photon336
\[\frac{ (1L)(2.66atm) }{ (5.33atm) } = 0.4 L~estimate \] the pressure went up so the volume went down. I didn't have a calculator i just estimated it.
Photon336
  • Photon336
that's essentially what boyles law is pressure goes up volume goes down. opposite is true too
CountryBoy15
  • CountryBoy15
0.499 and thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.