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NotTim
 one year ago
For each titration you will obtain a measured value table and two graphs. The measured value table
consists of the following : volume of HCl in mL, DV, pH, DpH and derivative DpH/DV. The first
graph is a plot of pH vs mL of 0.1 M HCl added. The steepest parts of the plot indicate the two
equivalence points (indicated by the dotted lines). The second graph is a first derivative plot of
DpH/DmL vs mL of 0.1 M HCl added. The two equivalence points are determined fr
NotTim
 one year ago
For each titration you will obtain a measured value table and two graphs. The measured value table consists of the following : volume of HCl in mL, DV, pH, DpH and derivative DpH/DV. The first graph is a plot of pH vs mL of 0.1 M HCl added. The steepest parts of the plot indicate the two equivalence points (indicated by the dotted lines). The second graph is a first derivative plot of DpH/DmL vs mL of 0.1 M HCl added. The two equivalence points are determined fr

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NotTim
 one year ago
Best ResponseYou've already chosen the best response.0From lab, "Potentiometric Acid Base Titration: Analysis of an Unknown Mixture Containing Carbonate and Bicarbonate Species (Automatic Titrator)"

NotTim
 one year ago
Best ResponseYou've already chosen the best response.0I already figured out R3 for 3 samples, which are 0.239 mmol, 0.238 mmol and 0.239 mmol.

NotTim
 one year ago
Best ResponseYou've already chosen the best response.0They're negative because for some awful reason my samples were extremely pure, and no extra signals were given at R2 for all of them.

dan815
 one year ago
Best ResponseYou've already chosen the best response.0@hwyl @abb0t @nincompoop @roast_master_says

NotTim
 one year ago
Best ResponseYou've already chosen the best response.0I think nincompoop hates my guts.

Shikamaru11
 one year ago
Best ResponseYou've already chosen the best response.0it was (y) means nice shot

dan815
 one year ago
Best ResponseYou've already chosen the best response.0i have brought u back to the land of chemistry

Shikamaru11
 one year ago
Best ResponseYou've already chosen the best response.0well is it a que. or just a procedure :P

NotTim
 one year ago
Best ResponseYou've already chosen the best response.0For each titration you will obtain a measured value table and two graphs. The measured value table consists of the following : volume of HCl in mL, DV, pH, DpH and derivative DpH/DV. The first graph is a plot of pH vs mL of 0.1 M HCl added. The steepest parts of the plot indicate the two equivalence points (indicated by the dotted lines). The second graph is a first derivative plot of DpH/DmL vs mL of 0.1 M HCl added. The two equivalence points are determined from the two maxima and the volumes of 0.1 M added to the equivalence points are recorded. The results are calculated according to the following formula: R1 = Q1 R2 = Q2 Where Q is the number of mmol of titrant that has been delivered. You will have to calculate a third result R3 which is: R3 = Q2 – Q1 This takes into account the mmol of the original carbonate that was converted into bicarbonate after the first equivalence point. Use the results obtained from R1 and R3 (in millimoles) to calculate the milligrams of sodium carbonate and sodium bicarbonate present in the original sample. Remember that you used 10 mL aliquot in the titration out of the total sample volume of 100 mL.

ChantySquirrel1129**
 one year ago
Best ResponseYou've already chosen the best response.1There ya go!

NotTim
 one year ago
Best ResponseYou've already chosen the best response.0Question specifically was "Use the results obtained from R1 and R3 (in millimoles) to calculate the milligrams of sodium carbonate and sodium bicarbonate present in the original sample.". I'm such a goof.

NotTim
 one year ago
Best ResponseYou've already chosen the best response.0R3 for 3 samples, which are 0.239 mmol, 0.238 mmol and 0.239 mmol.
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