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NotTim

  • one year ago

For each titration you will obtain a measured value table and two graphs. The measured value table consists of the following : volume of HCl in mL, DV, pH, DpH and derivative DpH/DV. The first graph is a plot of pH vs mL of 0.1 M HCl added. The steepest parts of the plot indicate the two equivalence points (indicated by the dotted lines). The second graph is a first derivative plot of DpH/DmL vs mL of 0.1 M HCl added. The two equivalence points are determined fr

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  1. NotTim
    • one year ago
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    From lab, "Potentiometric Acid Base Titration: Analysis of an Unknown Mixture Containing Carbonate and Bicarbonate Species (Automatic Titrator)"

  2. NotTim
    • one year ago
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    I already figured out R3 for 3 samples, which are -0.239 mmol, -0.238 mmol and -0.239 mmol.

  3. NotTim
    • one year ago
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    They're negative because for some awful reason my samples were extremely pure, and no extra signals were given at R2 for all of them.

  4. Shikamaru11
    • one year ago
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    :(y)

  5. NotTim
    • one year ago
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    What da ell was that

  6. dan815
    • one year ago
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    @hwyl @abb0t @nincompoop @roast_master_says

  7. NotTim
    • one year ago
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    I think nincompoop hates my guts.

  8. Shikamaru11
    • one year ago
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    it was (y) means nice shot

  9. dan815
    • one year ago
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    @Empty

  10. dan815
    • one year ago
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    i have brought u back to the land of chemistry

  11. ChantySquirrel1129**
    • one year ago
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    erm

  12. Shikamaru11
    • one year ago
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    well is it a que. or just a procedure :P

  13. NotTim
    • one year ago
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    For each titration you will obtain a measured value table and two graphs. The measured value table consists of the following : volume of HCl in mL, DV, pH, DpH and derivative DpH/DV. The first graph is a plot of pH vs mL of 0.1 M HCl added. The steepest parts of the plot indicate the two equivalence points (indicated by the dotted lines). The second graph is a first derivative plot of DpH/DmL vs mL of 0.1 M HCl added. The two equivalence points are determined from the two maxima and the volumes of 0.1 M added to the equivalence points are recorded. The results are calculated according to the following formula: R1 = Q1 R2 = Q2 Where Q is the number of mmol of titrant that has been delivered. You will have to calculate a third result R3 which is: R3 = Q2 – Q1 This takes into account the mmol of the original carbonate that was converted into bicarbonate after the first equivalence point. Use the results obtained from R1 and R3 (in millimoles) to calculate the milligrams of sodium carbonate and sodium bicarbonate present in the original sample. Remember that you used 10 mL aliquot in the titration out of the total sample volume of 100 mL.

  14. ChantySquirrel1129**
    • one year ago
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    There ya go!

  15. NotTim
    • one year ago
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    Question specifically was "Use the results obtained from R1 and R3 (in millimoles) to calculate the milligrams of sodium carbonate and sodium bicarbonate present in the original sample.". I'm such a goof.

  16. NotTim
    • one year ago
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    R3 for 3 samples, which are -0.239 mmol, -0.238 mmol and -0.239 mmol.

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