NotTim
  • NotTim
For each titration you will obtain a measured value table and two graphs. The measured value table consists of the following : volume of HCl in mL, DV, pH, DpH and derivative DpH/DV. The first graph is a plot of pH vs mL of 0.1 M HCl added. The steepest parts of the plot indicate the two equivalence points (indicated by the dotted lines). The second graph is a first derivative plot of DpH/DmL vs mL of 0.1 M HCl added. The two equivalence points are determined fr
Chemistry
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
NotTim
  • NotTim
From lab, "Potentiometric Acid Base Titration: Analysis of an Unknown Mixture Containing Carbonate and Bicarbonate Species (Automatic Titrator)"
NotTim
  • NotTim
I already figured out R3 for 3 samples, which are -0.239 mmol, -0.238 mmol and -0.239 mmol.
NotTim
  • NotTim
They're negative because for some awful reason my samples were extremely pure, and no extra signals were given at R2 for all of them.

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Shikamaru11
  • Shikamaru11
:(y)
NotTim
  • NotTim
What da ell was that
dan815
  • dan815
@hwyl @abb0t @nincompoop @roast_master_says
NotTim
  • NotTim
I think nincompoop hates my guts.
Shikamaru11
  • Shikamaru11
it was (y) means nice shot
dan815
  • dan815
@Empty
dan815
  • dan815
i have brought u back to the land of chemistry
ChantySquirrel1129**
  • ChantySquirrel1129**
erm
Shikamaru11
  • Shikamaru11
well is it a que. or just a procedure :P
NotTim
  • NotTim
For each titration you will obtain a measured value table and two graphs. The measured value table consists of the following : volume of HCl in mL, DV, pH, DpH and derivative DpH/DV. The first graph is a plot of pH vs mL of 0.1 M HCl added. The steepest parts of the plot indicate the two equivalence points (indicated by the dotted lines). The second graph is a first derivative plot of DpH/DmL vs mL of 0.1 M HCl added. The two equivalence points are determined from the two maxima and the volumes of 0.1 M added to the equivalence points are recorded. The results are calculated according to the following formula: R1 = Q1 R2 = Q2 Where Q is the number of mmol of titrant that has been delivered. You will have to calculate a third result R3 which is: R3 = Q2 – Q1 This takes into account the mmol of the original carbonate that was converted into bicarbonate after the first equivalence point. Use the results obtained from R1 and R3 (in millimoles) to calculate the milligrams of sodium carbonate and sodium bicarbonate present in the original sample. Remember that you used 10 mL aliquot in the titration out of the total sample volume of 100 mL.
ChantySquirrel1129**
  • ChantySquirrel1129**
There ya go!
NotTim
  • NotTim
Question specifically was "Use the results obtained from R1 and R3 (in millimoles) to calculate the milligrams of sodium carbonate and sodium bicarbonate present in the original sample.". I'm such a goof.
NotTim
  • NotTim
R3 for 3 samples, which are -0.239 mmol, -0.238 mmol and -0.239 mmol.

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