@musicdude x - 2y = 3 5x + 3y = 2 The lines whose equations are shown intersect at

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@musicdude x - 2y = 3 5x + 3y = 2 The lines whose equations are shown intersect at

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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have you learned substitution and/or elimination methods?
Yeah
We can solve this by using a method called elimination. You could use substitution too, but sometimes elimination makes life a bit simpler. Plus, students tend to lean away from elimination, but with practice it can be better the sub. We can multiply the top equation by -5. This gives us -5x + 10y = -15 5x + 3y = 2 13y = -13 y = -1 Now plug that sucker back into any of those equations and solve for x :)

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Sorry -- In the middle step, I added the two equations.

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