A community for students.
Here's the question you clicked on:
 0 viewing
marcelie
 one year ago
help please !!!! i attached the picture below
marcelie
 one year ago
help please !!!! i attached the picture below

This Question is Closed

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444196703724:dw

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444196743208:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooo, so logs are like exponents, when you multiply exponents, what do you do with them actually?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What's the answer to this question? x^2(x^2)?

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0the answer in my sheet says x cant equal 3 and x = 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hm, I don't think you can get an numerical answer to this question, because it doesn't have an equal sign.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But you can simplify the equation more

freckles
 one year ago
Best ResponseYou've already chosen the best response.5dw:1444197015545:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.5\[\log_2(x+2)+\log_2(x1)=2?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooo, that makes more sense.

freckles
 one year ago
Best ResponseYou've already chosen the best response.5that first step you have there looks great little confused on your third line you have you should do 2^ on both sides for your second line

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0the other one should be log base 2 (2) ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.5\[2^{\log_2((x1)(x+2))}=2^2\] see we do 2^ on both sides

freckles
 one year ago
Best ResponseYou've already chosen the best response.5this gives us: \[(x1)(x+2)=4\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.5you will need to expand and get everything on one side like you are going to want 0 on that right hand side there

freckles
 one year ago
Best ResponseYou've already chosen the best response.5or what I'm asking you to do?

marcelie
 one year ago
Best ResponseYou've already chosen the best response.0yes. why 2 on both sides

freckles
 one year ago
Best ResponseYou've already chosen the best response.5\[a^{\log_a(y)}=y \\ \text{ for } y>0 \text{ and } a \in (0,1) \cup (1,\infty)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.5\[\text{ that is I knew } 2^{\log_2((x+2)(x1))}=(x+2)(x1)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.5for example if we had: \[\log_{4}((x+2)(x1))=2 \\ \text{ I would do 4^ on both sides } \\ 4^{(\log_4(x+2)(x1))}=4^2 \\ \text{ which the whole point in doing the 4^ } \\ \text{ is written below } \\ (x+2)(x1)=4^2 \\ \text{ we get \to write in its equivalent exponent form } \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.5do you understand that the following two are inverses: \[y=a^x \text{ and } y=\log_a(x)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.5\[f(x)=a^x \text{ and } f^{1}(x)=\log_a(x) \text{ are inverses iff } \\ f(f^{1}(x))=x \text{ and } f^{1}(f(x))=x\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.5that is: \[a^{\log_a(x)}=x \text{ and } \log_a(a^x)=x\] there are some domain restrictions but yeah

freckles
 one year ago
Best ResponseYou've already chosen the best response.5\[\text{ so we had } \log_2(stuff)=2 \\ \text{ and I did } \color{red}{2}^{\log_\color{green}{2}(stuff)}=\color{red}{2}^2 \\ stuff=4\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.5I did 2^ on both sides because of the green 2 there

freckles
 one year ago
Best ResponseYou've already chosen the best response.5if the green would have been 5 I would have did 5^ on both sides

freckles
 one year ago
Best ResponseYou've already chosen the best response.5if that doesn't make sense to you I'm sure you have written log equations in their equivalent exponential form right?

freckles
 one year ago
Best ResponseYou've already chosen the best response.5\[\log_a(y)=x \implies a^{x}=y \\ \log_2([(x1)(x+2)]=2 \implies 2^{2}=(x1)(x+2)\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.