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Jadedry
 one year ago
Use pascals triangle to simplify:
Jadedry
 one year ago
Use pascals triangle to simplify:

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Jadedry
 one year ago
Best ResponseYou've already chosen the best response.0\[(1+\sqrt2)^3\] Where do I start? Thanks in advance!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you will start at the end the \[\sqrt{2}^{3}\]

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.0I should end up with: \[1 + (3 + 3\sqrt2) + (3+6) + 2^{1.5}\] right? But my textbook says: \[7+ 5\sqrt2\] how?

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1i dont understand why you're adding... but the idea seems to be there, here is my working out \[1(1)^3 + 3(1)^2(\sqrt{2}) + 3(1)(\sqrt{2} )^2 + (\sqrt{2} )^3\]

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1and that simplifies down to \[7 + 5\sqrt{2}\]

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1@Jadedry do you see why I did what I did?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you will start at the end the 2√3

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.0@FireKat97 Hello again, Firekat! You're absolutely right, I added when I should have multiplied. X.X Once question though, how does\[\sqrt 2 ^{3} = 2 \sqrt 2 ?\]

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1okay so you know how you have \[(\sqrt{2})^3\] that opens up to \[\sqrt{2}. \sqrt{2}. \sqrt{2}\] and when you multiply a root by itself, the roots cancel, so you get left with \[2\sqrt{2}\]

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1I hope that makes sense

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1and hey @Jadedry lol

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.0Ah that makes perfect sense I understand. ;u; Thanks for the help! closing this now!

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1But even when you had \[2^{3/2}\] you can break that down to \[2^1.2^{1/2}\] which is again \[2 \sqrt{2}\] so thats another way to think about it @Jadedry :)

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.0@FireKat97 Ooo! I got that. Interesting way of looking at it. thanks again. ;u;

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1@Jadedry no problem :)
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