steve816
  • steve816
Easy quick question!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
steve816
  • steve816
|dw:1444203627104:dw|
steve816
  • steve816
I feel stupid not knowing this, but I always don't know which term to square
FireKat97
  • FireKat97
\[(a \sqrt{b})^2 = (a)^2.(\sqrt{b})^2 = a^2.b\]

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steve816
  • steve816
Would the answer be 32?
FireKat97
  • FireKat97
The square root and the square cancel because a square root can also be write-in the form of \[(b)^{1/2}\] so when you square that you get \[(b)^{\frac{ 1 }{ 2 } . 2}\] and according to index laws the 1/2 and 2 cancel so you just get \[(b)^1 \] which is just (b)
FireKat97
  • FireKat97
yeah that correct
steve816
  • steve816
thanks mate
FireKat97
  • FireKat97
no problem :)

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