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FireKat97
 one year ago
I'm stuck on this question..
FireKat97
 one year ago
I'm stuck on this question..

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FireKat97
 one year ago
Best ResponseYou've already chosen the best response.0Oh on my screen Ive already posted it..

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0oh my bad.. didnt see that i can scroll it left :$

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0havent they given the answer already in the question a= 0.7m/s^2

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.0nope, thats what I thought too, but apparently thats yet another piece of info needed to get the answer out...

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.0I found this sample solution online but it made no sense to me tbh..

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0oh i think they have given the "total acceleration" which consist of the acceleration towards the center (maybe from air pressure or something) + accleration of the plane by itself. from radius of curvature you can find the perpendicular component . since total acceleration vector = perpendicular acceleraton component + acceleration vector of generated by the plane you can find the acceleration vector generated by the plane from that

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.0so the perpendicular component is the acceleration toward the centre?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0I guess so. That can be obtained with the radius of curvature

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.0ummm okay thanks, but how would we know to include the acceleration toward the centre?
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