## anonymous one year ago Pythagorean Thereom 3-D!!! Picture attached!

1. anonymous

@angel12310 You have to find DG first. $DG^2 = DC^2 + CG^2$ $AG^2 = DG^2 + AD^2$ Can you figure it out now?

3. anonymous

Nope...

@angel12310 You just have to substitute the names of lines for their lengths, try!

5. anonymous

:( ok

@angel12310 Just give it another bash, if you really, really have trouble please don't hesitate to ping me. c:

@angel12310 That equation is not possible. $DG^2 = 5^2 + 12^2$

8. anonymous

IDK!!!

9. anonymous

DG^2= 25+ 144

10. anonymous

DG^2=169

11. anonymous

Square root of 169

12. anonymous

13

13. anonymous

DG^2=13?

14. anonymous

13.0 cm?

Okay, $DG^2 = 5^2 +12^2$ Therefore DG = $\sqrt 169=13$ $AG^2 = DG^2 + 4^2$ =$AG^2 = 13^2 +4^2$ =$AG^2 = 185$ $\sqrt 185 = 13.6$ Therefore the answer is 13.6

16. anonymous

ok thx!

Remember that $AG^2 = Dg^2 + 4^2$ No problem! c:

18. anonymous

Can u help me with a few more?