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anonymous
 one year ago
Pythagorean Thereom 3D!!!
Picture attached!
anonymous
 one year ago
Pythagorean Thereom 3D!!! Picture attached!

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Jadedry
 one year ago
Best ResponseYou've already chosen the best response.2@angel12310 You have to find DG first. \[DG^2 = DC^2 + CG^2\] \[AG^2 = DG^2 + AD^2\] Can you figure it out now?

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.2@angel12310 You just have to substitute the names of lines for their lengths, try!

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.2@angel12310 Just give it another bash, if you really, really have trouble please don't hesitate to ping me. c:

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.2@angel12310 That equation is not possible. \[DG^2 = 5^2 + 12^2\]

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.2Okay, \[DG^2 = 5^2 +12^2\] Therefore DG = \[\sqrt 169=13\] \[AG^2 = DG^2 + 4^2\] =\[AG^2 = 13^2 +4^2\] =\[AG^2 = 185\] \[\sqrt 185 = 13.6\] Therefore the answer is 13.6

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.2Remember that \[AG^2 = Dg^2 + 4^2\] No problem! c:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can u help me with a few more?

Jadedry
 one year ago
Best ResponseYou've already chosen the best response.2@angel12310 Sure, I'll be on for a bit longer! c:
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