Help!! Write the equation of a line, in slope-intercept form, that is parallel to the line -12x+3y=23 , and passes through the point (2,-3).
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first we need to find the slope in the original equation because parallel lines have the same slope. We will put the equation in y = mx + b form where m is your slope.
-12x + 3y = 23 --- add 12x to both sides
3y = 12x + 23 -- now divide both sides by 3
y = 4x + 23/3
now the number in the m position, the slope, is 4
Our parallel line will have a slope of 4.
Now we will use y = mx + b again...
slope(m) = 4
(2,-3)...x = 2 and y = -3
and since we have our slope and our points (x,y), we just need to find b, the y intercept.
now we sub
-3 = 4(2) + b
-3 = 8 + b
-8-3 = b
-11 = b
so your parallel equation is : y = 4x + (-11) or y = 4x - 11
@texaschic101 Thanks and how about this ? Write the equation, in slope-intercept form, that is perpendicular to y=-1/2x-7 that passes through the point (-4, 5).