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VCabral1134
 one year ago
Plz help will medal and fan!
Match each sequence with a function that generates it.
a. f(n) = 3n, n ≥ 1 and n is an integer.
e. f(n) = n^2+ 2, n ≥ 1 and n is an integer.
b. f(n) = 2n(n+ 1), n ≥ 1 and n is an integer.
f. f(1) = 48 and f(n) = 1^2 f(n− 1), n ≥ 2 and n is an integer.
c. f(n) = 2(n+ 2), n ≥ 0 and n is an integer.
g. f(1) = 48 and f(n) = 2f(n− 1), n ≥ 2 and n is an integer.
d. f(n) = n− 1^n , n ≥ 1 and n is an integer.
h. f(n) = n^n+ 1, n ≥ 1 and n is an integer.
4, 12, 24, 40, 60, …
VCabral1134
 one year ago
Plz help will medal and fan! Match each sequence with a function that generates it. a. f(n) = 3n, n ≥ 1 and n is an integer. e. f(n) = n^2+ 2, n ≥ 1 and n is an integer. b. f(n) = 2n(n+ 1), n ≥ 1 and n is an integer. f. f(1) = 48 and f(n) = 1^2 f(n− 1), n ≥ 2 and n is an integer. c. f(n) = 2(n+ 2), n ≥ 0 and n is an integer. g. f(1) = 48 and f(n) = 2f(n− 1), n ≥ 2 and n is an integer. d. f(n) = n− 1^n , n ≥ 1 and n is an integer. h. f(n) = n^n+ 1, n ≥ 1 and n is an integer. 4, 12, 24, 40, 60, …

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0preetha never answers she owns openstudy shes a busy lady

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0welp im no good to help sorry

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Evaluate each function and find out the first two terms (the two starting values of n), and you will have a good idea where 4, 12, 24, 40.... fits.

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.1I also have these 0,1/2,2/3,3/4,4/5... 48, 24, 12, 6, 3, … 3, 6, 9, 12, 15, … 3, 6, 11, 18, 27,...

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.1I just need to find out which ones there not

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.1Then I could figure it out

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Example: a. f(n) = 3n, n ≥ 1 and n is an integer, i.e. f(n)=3n, n ≥ 1, n\(\in Z\) means n={1,2,3,4....} Substitute n into f(n) gives f(n)={3,6,9,12,.....} Now look to see if {3,6,9,12,....} fits into any of the required sequences, and there you go!
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