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VCabral1134

  • one year ago

Plz help will medal and fan! Match each sequence with a function that generates it. a. f(n) = 3n, n ≥ 1 and n is an integer. e. f(n) = n^2+ 2, n ≥ 1 and n is an integer. b. f(n) = 2n(n+ 1), n ≥ 1 and n is an integer. f. f(1) = 48 and f(n) = 1^2 f(n− 1), n ≥ 2 and n is an integer. c. f(n) = 2(n+ 2), n ≥ 0 and n is an integer. g. f(1) = 48 and f(n) = 2f(n− 1), n ≥ 2 and n is an integer. d. f(n) = n− 1^n , n ≥ 1 and n is an integer. h. f(n) = n^n+ 1, n ≥ 1 and n is an integer. 4, 12, 24, 40, 60, …

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  1. anonymous
    • one year ago
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    preetha never answers she owns openstudy shes a busy lady

  2. anonymous
    • one year ago
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    welp im no good to help sorry

  3. VCabral1134
    • one year ago
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    That's Ok

  4. VCabral1134
    • one year ago
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    @angel12310

  5. mathmate
    • one year ago
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    Evaluate each function and find out the first two terms (the two starting values of n), and you will have a good idea where 4, 12, 24, 40.... fits.

  6. VCabral1134
    • one year ago
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    I also have these 0,1/2,2/3,3/4,4/5... 48, 24, 12, 6, 3, … 3, 6, 9, 12, 15, … 3, 6, 11, 18, 27,...

  7. VCabral1134
    • one year ago
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    @mathmate

  8. VCabral1134
    • one year ago
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    I just need to find out which ones there not

  9. VCabral1134
    • one year ago
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    Then I could figure it out

  10. mathmate
    • one year ago
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    Example: a. f(n) = 3n, n ≥ 1 and n is an integer, i.e. f(n)=3n, n ≥ 1, n\(\in Z\) means n={1,2,3,4....} Substitute n into f(n) gives f(n)={3,6,9,12,.....} Now look to see if {3,6,9,12,....} fits into any of the required sequences, and there you go!

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