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anonymous
 one year ago
The electric force between a charged foam cup and a positively charged metal sphere is 2.12 newtons. If the charge on the cup is 2.0 × 106 coulombs and the charge on the metal sphere is 2.5 × 106 coulombs, what is the distance between the two? (k = 9.0 × 109 newton·meter2/coulombs2) i know the formula but dont know how to use it :(
anonymous
 one year ago
The electric force between a charged foam cup and a positively charged metal sphere is 2.12 newtons. If the charge on the cup is 2.0 × 106 coulombs and the charge on the metal sphere is 2.5 × 106 coulombs, what is the distance between the two? (k = 9.0 × 109 newton·meter2/coulombs2) i know the formula but dont know how to use it :(

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johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Hint, Coulombs Law states \(\large F = k\frac{q_1q_2}{r^2}\) Where F is the force between the 2 objects (given) Soo we can pug everything we have in \[\large 2.12N = (9.0\times 10^9 \frac{Nm^2}{C^2})(\frac{2.0 \times 10^{6}C2.5\times 10^{6}C}{r^2})\] So notice that we just want to solve for the distance between the 2...hence we just solve for 'r' \[\large r = \sqrt{\frac{ (9.0\times 10^9 \frac{Nm^2}{C^2})2.0 \times 10^{6}C2.5\times 10^{6}C}{2.12N}} = ?\]
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