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anonymous

  • one year ago

Simplify: ln e1

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  1. SolomonZelman
    • one year ago
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    \(\ln(e^1)\) ?

  2. SolomonZelman
    • one year ago
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    like that?

  3. anonymous
    • one year ago
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    yea like that

  4. misty1212
    • one year ago
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    \(e^1\)?? must be an algorithmically generated question a human being would write (e\)

  5. anonymous
    • one year ago
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    yes

  6. SolomonZelman
    • one year ago
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    Ok, you know that any number raised to an exponent of \(\color{black}{\LARGE _{^1}}\), is that number itself: \(\color{black}{a^1=a}\)

  7. anonymous
    • one year ago
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    oh wow that was so simple.

  8. SolomonZelman
    • one year ago
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    And, just like: \(\log_a(a)=1\) \(\log_e(e)=\ln(e)=?\)

  9. anonymous
    • one year ago
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    so it would be e?

  10. SolomonZelman
    • one year ago
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    again, I mentioned a property: \(\large \log_a(a)=1\) And number e also satisfies that property: So, the expression below would be equivalent to what? \(\large\log_e(e)=?\)

  11. anonymous
    • one year ago
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    1

  12. SolomonZelman
    • one year ago
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    Yes

  13. SolomonZelman
    • one year ago
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    So, \(\large\ln(e)=\log_e(e)=1\)

  14. anonymous
    • one year ago
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    thankyou thankyou thankyouu !

  15. SolomonZelman
    • one year ago
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    \(\color{blue}{\Large \mathbb{Y}\unicode{x22a1} \mathbb{U}~~ \mathbb{WELC} \unicode{x22a1}\mathbb{ME}}\)

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