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anonymous

  • one year ago

find a formula for the nth term {1/15, 3/20, 9/25, 27/30, 81/35}

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  1. AlexandervonHumboldt2
    • one year ago
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    look. the denominators of your fractions all have difference 5. the numenators have quotent 3. so your formula: \[a_n=\frac{3n-2 }{ 15 +5n }\]

  2. anonymous
    • one year ago
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    that does not work if I am correct when n=2 it will be 6-2 which is 4 on the numerator and 15+10 on the denom giving 4/25 for a2 when a2 = 3/20

  3. AlexandervonHumboldt2
    • one year ago
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    oops sorry. hold on a second i will redo

  4. AlexandervonHumboldt2
    • one year ago
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    a_n=3^n, where n_1=0

  5. AlexandervonHumboldt2
    • one year ago
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    so the whole formula will be \[a_n=\frac{3^n}{15+5n}\]

  6. anonymous
    • one year ago
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    no

  7. anonymous
    • one year ago
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    im not sure you know what you are doing

  8. anonymous
    • one year ago
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    you realize that n=1 is the first term, n=2 is the second term, n=3 is the third term........

  9. AlexandervonHumboldt2
    • one year ago
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    @freckles sequence problem

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