anonymous
  • anonymous
find a formula for the nth term {1/15, 3/20, 9/25, 27/30, 81/35}
Mathematics
chestercat
  • chestercat
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AlexandervonHumboldt2
  • AlexandervonHumboldt2
look. the denominators of your fractions all have difference 5. the numenators have quotent 3. so your formula: \[a_n=\frac{3n-2 }{ 15 +5n }\]
anonymous
  • anonymous
that does not work if I am correct when n=2 it will be 6-2 which is 4 on the numerator and 15+10 on the denom giving 4/25 for a2 when a2 = 3/20
AlexandervonHumboldt2
  • AlexandervonHumboldt2
oops sorry. hold on a second i will redo

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AlexandervonHumboldt2
  • AlexandervonHumboldt2
a_n=3^n, where n_1=0
AlexandervonHumboldt2
  • AlexandervonHumboldt2
so the whole formula will be \[a_n=\frac{3^n}{15+5n}\]
anonymous
  • anonymous
no
anonymous
  • anonymous
im not sure you know what you are doing
anonymous
  • anonymous
you realize that n=1 is the first term, n=2 is the second term, n=3 is the third term........
AlexandervonHumboldt2
  • AlexandervonHumboldt2
@freckles sequence problem

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