## anonymous one year ago find a formula for the nth term {1/15, 3/20, 9/25, 27/30, 81/35}

1. AlexandervonHumboldt2

look. the denominators of your fractions all have difference 5. the numenators have quotent 3. so your formula: $a_n=\frac{3n-2 }{ 15 +5n }$

2. anonymous

that does not work if I am correct when n=2 it will be 6-2 which is 4 on the numerator and 15+10 on the denom giving 4/25 for a2 when a2 = 3/20

3. AlexandervonHumboldt2

oops sorry. hold on a second i will redo

4. AlexandervonHumboldt2

a_n=3^n, where n_1=0

5. AlexandervonHumboldt2

so the whole formula will be $a_n=\frac{3^n}{15+5n}$

6. anonymous

no

7. anonymous

im not sure you know what you are doing

8. anonymous

you realize that n=1 is the first term, n=2 is the second term, n=3 is the third term........

9. AlexandervonHumboldt2

@freckles sequence problem