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anonymous
 one year ago
find a formula for the nth term {1/15, 3/20, 9/25, 27/30, 81/35}
anonymous
 one year ago
find a formula for the nth term {1/15, 3/20, 9/25, 27/30, 81/35}

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AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.0look. the denominators of your fractions all have difference 5. the numenators have quotent 3. so your formula: \[a_n=\frac{3n2 }{ 15 +5n }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that does not work if I am correct when n=2 it will be 62 which is 4 on the numerator and 15+10 on the denom giving 4/25 for a2 when a2 = 3/20

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.0oops sorry. hold on a second i will redo

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.0a_n=3^n, where n_1=0

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.0so the whole formula will be \[a_n=\frac{3^n}{15+5n}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure you know what you are doing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you realize that n=1 is the first term, n=2 is the second term, n=3 is the third term........

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.0@freckles sequence problem
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