## anonymous one year ago What is the equation of the oblique asymptote? h(x) = x^2-3x-4/x+1 a y=x+4 b y=x^2-3 c y=x d y=x-4

1. misty1212

HI!!

2. misty1212

divide

3. misty1212

you will get a quotient and a remainder ignore the remainder, the quotient is your obliques asymptote

4. anonymous

5. anonymous

@misty1212

6. campbell_st

that's correct

7. anonymous

awesome Thanks!

8. campbell_st

well it's not awesome as the equation doesn't have an oblique asymptote... if you factor the numerator $\frac{x^2 - 3x -4}{x +1} = \frac{(x - 4)(x + 1)}{x +1}$ you'll find the equation simplifies to a linear form y = x - 4 and there is a point of discontinuity at x = -1 hope it helps