## anonymous one year ago (4x+f(x)) / (3−g(x)) can i get help to find the derivative using the quotient rule, thanks.

1. anonymous

@Loser66

2. johnweldon1993

We have to use the quotient rule? Alright well we know it can be written as $$\Large \frac{b(x)a'(x) - a(x)b'(x)}{b(x)^2}$$ Knowing the top is a(x) and the bottom is b(x) $\large a(x) = 4x + f(x)$ $\large a'(x) = 4 + f'(x)$ $\large b(x) = 3 - g(x)$ $\large b'(x) = -g'(x)$ so $\large \frac{(3 - g(x))(4 + f'(x)) - (4x + f(x))(-g'(x))}{(3 - g(x))(3 - g(x))}$ There is't really TOO much to simplify from there...but if you need to you can

3. anonymous

thank you! i have been stuck on this problem for a while now.