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anonymous

  • one year ago

I'm trying to solve the bisection problem from PS 1, what is wrong with my code:

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  1. anonymous
    • one year ago
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  2. kva1992
    • one year ago
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    why are you declaring NB so early why not just put x there instead of NB? Feels very Redundant(feels like more bytes for no reason) i would only set nb = to x*(1+MIR) -MMP I would personally say that should be your only reference but that is just my preference

  3. kva1992
    • one year ago
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    also would your high be calculated like so? (x*((1.0+(y/12.0))**12))/12.0

  4. kva1992
    • one year ago
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    Shouldnt it be that so it doesnt end up becoming a negative even if you are taking the abs of the value MMP = (low+high)/2.0

  5. anonymous
    • one year ago
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    I declared NB early because I thought NB had to be defined before I could start my loop. I'm going to implement your edits and see if it works, thank you

  6. anonymous
    • one year ago
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    Did you solve it already? I would really appreciate if you could attach your answer.

  7. anonymous
    • one year ago
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    One thing I'd recommend is examining what happens in your `for` loop with both the `month` variable and what happens to `high` and `low` when `NB` goes from positive to negative. Perhaps use a debug print statement like `print high == low`. Afterward I would recommend thinking about whether, if the payment is able to be made in 11 months rather than 12, will your program ever recognize that fact? Consider using a conditional and the `break` statement.

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