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anonymous
 one year ago
I'm trying to solve the bisection problem from PS 1, what is wrong with my code:
anonymous
 one year ago
I'm trying to solve the bisection problem from PS 1, what is wrong with my code:

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kva1992
 one year ago
Best ResponseYou've already chosen the best response.0why are you declaring NB so early why not just put x there instead of NB? Feels very Redundant(feels like more bytes for no reason) i would only set nb = to x*(1+MIR) MMP I would personally say that should be your only reference but that is just my preference

kva1992
 one year ago
Best ResponseYou've already chosen the best response.0also would your high be calculated like so? (x*((1.0+(y/12.0))**12))/12.0

kva1992
 one year ago
Best ResponseYou've already chosen the best response.0Shouldnt it be that so it doesnt end up becoming a negative even if you are taking the abs of the value MMP = (low+high)/2.0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I declared NB early because I thought NB had to be defined before I could start my loop. I'm going to implement your edits and see if it works, thank you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Did you solve it already? I would really appreciate if you could attach your answer.

anonymous
 11 months ago
Best ResponseYou've already chosen the best response.0One thing I'd recommend is examining what happens in your `for` loop with both the `month` variable and what happens to `high` and `low` when `NB` goes from positive to negative. Perhaps use a debug print statement like `print high == low`. Afterward I would recommend thinking about whether, if the payment is able to be made in 11 months rather than 12, will your program ever recognize that fact? Consider using a conditional and the `break` statement.
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