anonymous
  • anonymous
WILL MEDAL Solve each equation. Check your answer: 4 &1/4= 1 &3/4 + p
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Mehek14
  • Mehek14
\(\tt{4\dfrac{1}{4}=1\dfrac{3}{4}+p}\) <- like that?
anonymous
  • anonymous
yes
Mehek14
  • Mehek14
turn both numbers into improper fractions do you know how to do that?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
cant really remember right now. eek.
Mehek14
  • Mehek14
4*4 = 16 16 + 1 = 17 \(\dfrac{17}{4}\)
Mehek14
  • Mehek14
multiply the whole number by the denominator and add the numerator
anonymous
  • anonymous
o.k. just a second.
anonymous
  • anonymous
o.k. 17/4 - 7/4 = 2.5 or 5/2. now what
Mehek14
  • Mehek14
o.O where did you get the other numbers from?
anonymous
  • anonymous
whattttttt?
Mehek14
  • Mehek14
\(\tt{4\dfrac{1}{4}=\dfrac{17}{4}\\1\dfrac{3}{4}=\dfrac{7}{4}}\) <- like that?
Mehek14
  • Mehek14
Oh wait you solved it
Mehek14
  • Mehek14
my bad I didn't see that you are correct p = 5/2
anonymous
  • anonymous
thanks.
Mehek14
  • Mehek14
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.