anonymous
  • anonymous
can someone please help me y=x^2-36 y=x-16
Mathematics
jamiebookeater
  • jamiebookeater
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Vocaloid
  • Vocaloid
im guessing you want to solve the system? start by setting the two equations equal to each other x^2 - 36 = x - 16 know where to go from here?
anonymous
  • anonymous
not really
Vocaloid
  • Vocaloid
ok, now re-arrange the variables to get it into quadratic form x^2 - x - 20 = 0

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anonymous
  • anonymous
ok
Vocaloid
  • Vocaloid
then factor
anonymous
  • anonymous
so would that be x^2-36x-20=x
anonymous
  • anonymous
or is it x^2-36x-20=0
Vocaloid
  • Vocaloid
nope, remember, to factor, we want to find two numbers that add to -1 and multiply to get -20
Vocaloid
  • Vocaloid
x^2 - x - 20 = 0 (x-5)(x+4) = 0 so x = 5 and x = -4 now find the matching y values
Vocaloid
  • Vocaloid
still there?

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