M_M13
  • M_M13
will medal
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Whats your question?
M_M13
  • M_M13
2(2x + 5) = 4(X + 3)
M_M13
  • M_M13
how many solutions does this question have a. 1 b. infinite c. none

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anonymous
  • anonymous
2(2x + 5) = 4(X + 3) 4x + 10 = 4x + 12 4x + 10 - 10 = 4x + 12 - 10 4x = 4x + 2 4x - 4x = 4x - 4x + 2 0 = 2 So, how many solutions can this line have? Do you know?
M_M13
  • M_M13
I don't know, how do you know how many?
anonymous
  • anonymous
First you need to distribute any numbers outside of the parenthesis through the parenthesis (that was a horrible explanation I'm sorry...) 2(2x+5)=4(x+3) 4x+10=4x+3 then you try to get x on one side of the equation so you can solve for it. 4x-4x=0 10≠3 , therefore there are no solutions to the equation
M_M13
  • M_M13
oh
anonymous
  • anonymous
infinite solutions would be like if the equation was 3 = 3, as any number could be placed in x to solve the equation. one solution would be like x = 3, as only one number can equal x for the problem to be correct. no solution would be 4 = 7, as this is incorrect, and no number can be placed in x for it to work
M_M13
  • M_M13
so the answer to the question is c) no solution
anonymous
  • anonymous
Yes
M_M13
  • M_M13
thank you

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