marigirl
  • marigirl
Is it possible to model a Cubic so that it has a maximum of (30,12). See my drawing below
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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marigirl
  • marigirl
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SolomonZelman
  • SolomonZelman
Cubic function doesn't have an absolute max or absolute minimum if that is what you are referring to.
SolomonZelman
  • SolomonZelman
We can model a local maximum at (30,12) if you meant that.

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marigirl
  • marigirl
use the point (30,12) and find 𝑦=1/6750 𝑥(𝑥−60)(𝑥−120),
marigirl
  • marigirl
but still it is not the maximum......... prob cuz it doesnt have it (like you said)
SolomonZelman
  • SolomonZelman
here: desmos.com use that calculator to graph your equation, and you will see that (30,12) is not the local maximum (in fact not even a point on the function).
marigirl
  • marigirl
thanks :)
SolomonZelman
  • SolomonZelman
You can do this: \(y=\left(x-30\right)^3+12\) (Shift a parent function x³ by 30 units to the right, and by 12 units up)
SolomonZelman
  • SolomonZelman
Doesn't that function seem to have a local maximum at (30,12)?
SolomonZelman
  • SolomonZelman
Or even better, \(y=\left(x-30\right)^3-\left(x-30\right)^2+12\)
SolomonZelman
  • SolomonZelman
the second part I added, fixes the chape of the local maximum.
marigirl
  • marigirl
great. thanks heaps. I really appreciate it!
SolomonZelman
  • SolomonZelman
Sure, yw

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