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marigirl

  • one year ago

Is it possible to model a Cubic so that it has a maximum of (30,12). See my drawing below

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  1. marigirl
    • one year ago
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    |dw:1444251155105:dw|

  2. SolomonZelman
    • one year ago
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    Cubic function doesn't have an absolute max or absolute minimum if that is what you are referring to.

  3. SolomonZelman
    • one year ago
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    We can model a local maximum at (30,12) if you meant that.

  4. marigirl
    • one year ago
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    use the point (30,12) and find 𝑦=1/6750 𝑥(𝑥−60)(𝑥−120),

  5. marigirl
    • one year ago
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    but still it is not the maximum......... prob cuz it doesnt have it (like you said)

  6. SolomonZelman
    • one year ago
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    here: desmos.com use that calculator to graph your equation, and you will see that (30,12) is not the local maximum (in fact not even a point on the function).

  7. marigirl
    • one year ago
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    thanks :)

  8. SolomonZelman
    • one year ago
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    You can do this: \(y=\left(x-30\right)^3+12\) (Shift a parent function x³ by 30 units to the right, and by 12 units up)

  9. SolomonZelman
    • one year ago
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    Doesn't that function seem to have a local maximum at (30,12)?

  10. SolomonZelman
    • one year ago
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    Or even better, \(y=\left(x-30\right)^3-\left(x-30\right)^2+12\)

  11. SolomonZelman
    • one year ago
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    the second part I added, fixes the chape of the local maximum.

  12. marigirl
    • one year ago
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    great. thanks heaps. I really appreciate it!

  13. SolomonZelman
    • one year ago
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    Sure, yw

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