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marigirl
 one year ago
Is it possible to model a Cubic so that it has a maximum of (30,12).
See my drawing below
marigirl
 one year ago
Is it possible to model a Cubic so that it has a maximum of (30,12). See my drawing below

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marigirl
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444251155105:dw

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Cubic function doesn't have an absolute max or absolute minimum if that is what you are referring to.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1We can model a local maximum at (30,12) if you meant that.

marigirl
 one year ago
Best ResponseYou've already chosen the best response.0use the point (30,12) and find 𝑦=1/6750 𝑥(𝑥−60)(𝑥−120),

marigirl
 one year ago
Best ResponseYou've already chosen the best response.0but still it is not the maximum......... prob cuz it doesnt have it (like you said)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1here: desmos.com use that calculator to graph your equation, and you will see that (30,12) is not the local maximum (in fact not even a point on the function).

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1You can do this: \(y=\left(x30\right)^3+12\) (Shift a parent function x³ by 30 units to the right, and by 12 units up)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Doesn't that function seem to have a local maximum at (30,12)?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Or even better, \(y=\left(x30\right)^3\left(x30\right)^2+12\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1the second part I added, fixes the chape of the local maximum.

marigirl
 one year ago
Best ResponseYou've already chosen the best response.0great. thanks heaps. I really appreciate it!
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