## anonymous one year ago Find the sine, cosine, and tangent of 45 degrees. Sin 45 degrees = negative square root of 2 divided by 2, cos 45 degrees = negative square root of 2 divided by 2, tan 45 degrees = negative square root of 2 Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = square root of 2 Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = 1 Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = −1

1. johnweldon1993

Remember your special triangles, it can make a problem like this very quick A 45-45-90 triangle |dw:1444252285965:dw|

2. johnweldon1993

$\large sin(\theta) = \frac{opposite}{hypotenuse}$ $\large cos(\theta) = \frac{adjacent}{hypotenuse}$ $\large tan(\theta) = \frac{opposite}{adjacent}$

3. anonymous

oh now i remember!!! thank you so mcuh!

4. johnweldon1993

No problem :)