A ball is shot from a cannon into the air with an upward velocity of 40 ft/sec. The equation that gives the height (h) of the ball at any time (t) is: h(t)= -16t2 + 40ft + 1.5. Find the maximum height attained by the ball.

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\(\tt{x=\dfrac{-b}{2a}}\)

\[\frac{ -b }{ 2a}\] \[\frac{ -40 }{ -32 }\]
Time = 8

What is your equation exactly?

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