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narissa

  • one year ago

help

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  1. narissa
    • one year ago
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  2. anonymous
    • one year ago
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    What do you think it is?

  3. narissa
    • one year ago
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    is it d?

  4. anonymous
    • one year ago
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    No, do you want me to guide you through it or do you want to try one more time?

  5. calculusxy
    • one year ago
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    \[\large (2.5 \times 9)(10^{-8} \times 10^{-9})\] However, remember that the bases (in scientific notation) needs to be between 1 and 10.

  6. anonymous
    • one year ago
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    ^

  7. narissa
    • one year ago
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    explain

  8. calculusxy
    • one year ago
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    Your product is really 22.5 (which is not between 1 and 10) so you need to move the decimal place to the left to make it 2.25 (which is between 1 and 10).

  9. calculusxy
    • one year ago
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    When you do that, you need to do an extra step

  10. narissa
    • one year ago
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    wow confusing

  11. anonymous
    • one year ago
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    When you multiply 2.5 and 9, you get 22.5, which is not in scientific notation, so you must change it back

  12. calculusxy
    • one year ago
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    \[\huge 2.25 \times 10^1 \times 10^{-18}\]

  13. narissa
    • one year ago
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    so a

  14. calculusxy
    • one year ago
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    \[\huge 10^1 \] is needed because you moved the decimal one place to the left. Now the reverse can be applied to when you need to move the decimal place to the left. \[\huge 10^{-1}\]

  15. anonymous
    • one year ago
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    No, it will still be negative

  16. calculusxy
    • one year ago
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    Not really what is \[\large 1 + {-18} \]

  17. calculusxy
    • one year ago
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    That will be your exponent, while 2.25 is your base.

  18. narissa
    • one year ago
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    -17

  19. calculusxy
    • one year ago
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    Good.. so what's your final answer now?

  20. narissa
    • one year ago
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    thanks both of u

  21. narissa
    • one year ago
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    c

  22. anonymous
    • one year ago
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    Yes

  23. calculusxy
    • one year ago
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    Correct!

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spraguer (Moderator)
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