I got stuck partway through a problem!
Last year, Central High's yearbook costs $75 and only 500 were sold. A really smart math student realized that for every $5 in reduction in price, 100 more students will buy yearbooks. What price should be charged so that the school maximizes revenue from yearbook sales?
I know that if x = cost of a yearbook and y = the number sold then xy = R, (R= the revenue). Then I know that for n number of reductions in price the yearbook will cost 75-5n and 500+100n students will buy the yearbook. And then I'm stuck ;A;
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
x = number of reductions of $5 in the price of the yearbook
y = total revenue from selling 500+100x books
total revenue = (price per book)*(number of books)
y = (75-5x)*(500+100x)
y = 75*(500+100x) - 5x*(500+100x)
y = 75*(500)+75*(100x) - 5x*(500) - 5x*(100x)
y = 37500 + 7500x - 2500x - 500x^2
y = -500x^2 + 5000x + 37500
Do you see where to go from here?
Ohmygosh thank you so much!! I totally see what to do now! You're the best!