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  • one year ago

I got stuck partway through a problem! Last year, Central High's yearbook costs $75 and only 500 were sold. A really smart math student realized that for every $5 in reduction in price, 100 more students will buy yearbooks. What price should be charged so that the school maximizes revenue from yearbook sales? I know that if x = cost of a yearbook and y = the number sold then xy = R, (R= the revenue). Then I know that for n number of reductions in price the yearbook will cost 75-5n and 500+100n students will buy the yearbook. And then I'm stuck ;A;

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  1. jim_thompson5910
    • one year ago
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    Let x = number of reductions of $5 in the price of the yearbook y = total revenue from selling 500+100x books total revenue = (price per book)*(number of books) y = (75-5x)*(500+100x) y = 75*(500+100x) - 5x*(500+100x) y = 75*(500)+75*(100x) - 5x*(500) - 5x*(100x) y = 37500 + 7500x - 2500x - 500x^2 y = -500x^2 + 5000x + 37500 Do you see where to go from here?

  2. cocoacat
    • one year ago
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    Ohmygosh thank you so much!! I totally see what to do now! You're the best!

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