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Ac3

  • one year ago

Simplify the following expression.

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  1. Ac3
    • one year ago
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    \[\sqrt{(7xcosx)^2+(-7xsinx+14cosx)^2}\]

  2. Ac3
    • one year ago
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    the farthest i got to was\[\sqrt{49x^2-196sinxcosx+196\cos^2x}\]

  3. Ac3
    • one year ago
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    We want the radical to go away if possible or get the least amount of terms under the radical at least.

  4. Ac3
    • one year ago
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    Any idea @Preetha ?

  5. anonymous
    • one year ago
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    if you are lucky it is a prefect square

  6. anonymous
    • one year ago
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    doesn't look like one though, maybe some other trick

  7. Ac3
    • one year ago
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    I factored out a 49 and pulled it out of the radical. I was thinking maybe a trig identity for cos^2x not sure though.

  8. freckles
    • one year ago
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    was that thing really the initial problem?

  9. Ac3
    • one year ago
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    Well if you want the initial problem I'll go ahead and give it to you.

  10. anonymous
    • one year ago
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    the 49 comes out for sure not sure what else you can do here

  11. anonymous
    • one year ago
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    graph if cool http://www.wolframalpha.com/input/?i=sqrt%28%287xcos%28x%29%29^2%2B%28-7xsin%28x%29%2B14cos%28x%29%29^2%29

  12. anonymous
    • one year ago
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    *is

  13. Ac3
    • one year ago
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    r(t)=(7tsint+7cost)i + 7j + (7tcost-7sint)k, Find the Tangential, Normal, Binormal, and the Torsion.

  14. Ac3
    • one year ago
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    I think that's as far as it's going to go if I pull out the 49.

  15. freckles
    • one year ago
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    tangential is just ... \[|r'(t)| \text{ }\] \[r'(t)=[7 \sin(t)+7t \cos(t)-7\sin(t)]i+[0]j+[7 \cos(t)-7 t \sin(t)-7 \cos(t)]k \\ r'(t)=7 t \cos(t) i -7t \sin(t) k\]

  16. freckles
    • one year ago
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    \[|r'(t)|=\sqrt{(7 t \cos(t))^2+(-7 t \sin(t))^2}\]

  17. freckles
    • one year ago
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    this looks prettier

  18. Ac3
    • one year ago
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    wait hold on let me check your derivative because I checked mine like 4 times.

  19. freckles
    • one year ago
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    it looks like your k component was different

  20. freckles
    • one year ago
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    yeah seems like you wrote 7cos(t)-7 cos(t) as 7 cos(t)+7 cos(t) instead

  21. Ac3
    • one year ago
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    ahhhhhhhh i screwed up the last part!!!!!

  22. Ac3
    • one year ago
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    thanks freckles.

  23. freckles
    • one year ago
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    np

  24. Ac3
    • one year ago
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    derivative of -7sint = 7cost <--- lmfao i'm an idiot.

  25. freckles
    • one year ago
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    maybe for a sec you got antiderivative and derivative mixed up :p it happens to all of us especially on those crazy trig functions

  26. Ac3
    • one year ago
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    It happens to me all the time.

  27. Ac3
    • one year ago
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    I've been doing way too many integrals

  28. freckles
    • one year ago
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    anyways glad i can help

  29. Ac3
    • one year ago
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    see ya man thx again!

  30. freckles
    • one year ago
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    peace

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