## anonymous one year ago "find all real solutions" 5x^4+29x^3-x^2+29x-6 = 0 HELP PLEASE PRECAL IS SO HARD!

1. SolomonZelman

$$\large\color{black}{ \displaystyle 5x^4+29x^3-x^2+29x-6=\left(5x-1\right)\left(x+6\right)\left(x^2+1\right)}$$

2. SolomonZelman

After factoring, you can solve for x by solving three separate cases. *{1}* $$\large\color{black}{ \displaystyle \left(5x-1\right)=0\\[0.5em] }$$ *{2}* $$\large\color{black}{ \displaystyle \left(x+6\right)=0\\[0.5em]}$$ *{3}* $$\large\color{black}{ \displaystyle \left(x^2+1\right)=0\\[0.5em]}$$

3. SolomonZelman

If you are *not* considering any *imaginary* solutions, then case *{3}* will not have any solutions.