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haleyelizabeth2017
 one year ago
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
I know the vertical asymptote deals only with the denominator, which in this case, is x^2c.
haleyelizabeth2017
 one year ago
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c. I know the vertical asymptote deals only with the denominator, which in this case, is x^2c.

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle f(x)=\frac{1}{x^2c} }\) \(\large\color{black}{ \displaystyle f(x)=\frac{1}{(x\sqrt{c})(x+\sqrt{c})} }\)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1`The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3` means f(3) is undefined and the denominator `x^2c` is equal to 0 when x = 3 x^2c = 3^2  c = 9  c = 0 solve 9c = 0 for c

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1This function will have two vertical asymptotes: *[1]* \(\large\color{black}{ \displaystyle x=\sqrt{c}}\) *[2]* \(\large\color{black}{ \displaystyle x=\sqrt{c}}\)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1C is equal to 9

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1so \[\pm 9\] are the vertical asymptotes?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1No, the vertical asymptotes are: *±√9*

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1no, you just found c = 9 9 isn't an asymptote

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Yes, so your asymptotes are? (just to verify)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Wait...c has two values?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1nope, just one and it's c = 9 SolomonZelman is asking a slightly different related question

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, C is one value and it is 9. (we said that before) \(\large\color{black}{ \displaystyle f(x)=\frac{1}{x^29}=\frac{1}{(x+3)(x3)} }\) the function is undefined (because of the denominator) at *x=3* and *x=3*.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1but, the answer to your question (to find the number C, such that there is going to be a vertical asymptote at x=3), that is C=9.

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Sorry, I was confused before, so I had to clarify lol

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Nope, thank you very much
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