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calculusxy
 one year ago
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calculusxy
 one year ago
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calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, \frac{ 11 }{ 7 }, 7 \right\}\] \[\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}\] If n is a member of both set A and set B above, which of the following must be true? I. n is an integer II. 4n is an integer III. n = 4 (A) None (B) II only (C) I an II only (D) I and III only (E) I, II, and III

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, 4, \frac{ 11 }{ 7 }, 7 \right\}\] \[\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}\]

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.3well, first step is to see which elements are common to both sets

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0Well I know that III should be correct since 4 appears on both sets.

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.34/7, 4, and 7 are common, so n could be any one of these three options

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0You're looking at the second one right?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0Wait.. would it be none?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.3since n has three possibilities, we know that III is out
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