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calculusxy

  • one year ago

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  1. calculusxy
    • one year ago
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    \[\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, \frac{ 11 }{ 7 }, 7 \right\}\] \[\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}\] If n is a member of both set A and set B above, which of the following must be true? I. n is an integer II. 4n is an integer III. n = 4 (A) None (B) II only (C) I an II only (D) I and III only (E) I, II, and III

  2. calculusxy
    • one year ago
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    @Vocaloid

  3. calculusxy
    • one year ago
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    \[\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, 4, \frac{ 11 }{ 7 }, 7 \right\}\] \[\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}\]

  4. Vocaloid
    • one year ago
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    well, first step is to see which elements are common to both sets

  5. calculusxy
    • one year ago
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    Well I know that III should be correct since 4 appears on both sets.

  6. Vocaloid
    • one year ago
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    nope, not quite.

  7. Vocaloid
    • one year ago
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    4/7, 4, and 7 are common, so n could be any one of these three options

  8. calculusxy
    • one year ago
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    You're looking at the second one right?

  9. calculusxy
    • one year ago
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    Wait.. would it be none?

  10. Vocaloid
    • one year ago
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    that's correct

  11. Vocaloid
    • one year ago
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    since n has three possibilities, we know that III is out

  12. calculusxy
    • one year ago
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    Thank you!

  13. Vocaloid
    • one year ago
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    no problem ^_^~

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