## calculusxy one year ago Question posted below...

1. calculusxy

$\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, \frac{ 11 }{ 7 }, 7 \right\}$ $\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}$ If n is a member of both set A and set B above, which of the following must be true? I. n is an integer II. 4n is an integer III. n = 4 (A) None (B) II only (C) I an II only (D) I and III only (E) I, II, and III

2. calculusxy

@Vocaloid

3. calculusxy

$\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, 4, \frac{ 11 }{ 7 }, 7 \right\}$ $\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}$

4. Vocaloid

well, first step is to see which elements are common to both sets

5. calculusxy

Well I know that III should be correct since 4 appears on both sets.

6. Vocaloid

nope, not quite.

7. Vocaloid

4/7, 4, and 7 are common, so n could be any one of these three options

8. calculusxy

You're looking at the second one right?

9. calculusxy

Wait.. would it be none?

10. Vocaloid

that's correct

11. Vocaloid

since n has three possibilities, we know that III is out

12. calculusxy

Thank you!

13. Vocaloid

no problem ^_^~