Find the missing coefficient. (4d-4)(3d-2)= 12d^2 + blank d+8

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Find the missing coefficient. (4d-4)(3d-2)= 12d^2 + blank d+8

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4 –20 –4 20
LHS = (4d-4)(3d-2) = (4d)(3d) + (4d)(-2) + (-4)(3d) + (-4)(-2) = 12d^2 – 8d – 12d +8 = 12d^2 – 20d + 8 ------ (1) But RHS = 12d^2 + _d + 8 ---------(2) Therefore from (1) and (2), Missing Coefficient is -20.
hint: expand and simplify the left-hand-side

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Use the FOIL method.
\[\left( 4d-4 \right)\left( 3d-2 \right)=12d^2+[blank]d + 8\]
I just gave her the answer and everyone is ignoring it lol
yes, so expand and simplify the left-hand-side it'd end up in a quadratic, and you'd see the middle term :)
\[(4d-4)(3d-2) = 4d(3d) \times 4d(-2) \times -4(3d) \times -4(-2)\]
I am pretty sure that this is the foil method right?
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what do u mean by expand?
oh okay
Thank you guys!
Did you get your answer?
Yes well @arivillafana gave it to me
Could u help me with this question? Match the expression with its name. 3x3 – 3x + 3 quadratic binomial cubic trinomial fourth-degree monomial not a polynomial
cubic
Are u sure?
I have a great grade right now & just dont wanna loose it haha
that's what i think the expression has 3 terms a leading term with a power of 3 is a cubic
Oh okay ur right
@calculusxy when i calculated that i came up with 132?

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