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anonymous
 one year ago
For an angle Θ with the point (16, −30) on its terminating side, what is the value of cosine?
anonymous
 one year ago
For an angle Θ with the point (16, −30) on its terminating side, what is the value of cosine?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(16\) over the hypotenuse of the triangle with one side \(16\) and the other \(30\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i.e. \[\frac{16}{\sqrt{16^2+30^2}}\] as a start

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You need to solve for c. a2+b2=c2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@PrincessHush nice picture!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! (: @satellite73

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1Doesn't theta in this case have one side on the xaxis? dw:1444266733897:dw

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1cos(theta) = adjacent side over hypotenuse

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g(x) = 4 sin(4x) − 3, what is the value of the y intercept?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cos(Θ) = x/r = x/sqrt(x^2 + y^2) = 16/sqrt[16^2 + (−30)^2] = 16/34 = 8/17.

Deadly_Roses
 one year ago
Best ResponseYou've already chosen the best response.0princess is correct, it would be 8/17

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0rose, can you clarify the earlier comments for me? i don't quite understand what they were saying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes @gahoolianowl it is 8/17 and I would help you step by step but unfortunately I have to go I hope @Deadly_Roses can help you with whatever you need or if she cant ill try to get you help if you would like met to.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you for all of your help. it is very much appreciated. im sure rose will do wonderfully. she has yet to let me down with this stuff

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1You'll need to learn these. See attachment.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i haven't seen those since geometry 4 years ago 0.0 i forgot all about them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the 32nd term of the arithmetic sequence where a1 = −32 and a9 = −120?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The 32nd term of the arithmetic sequence where a1 = 32 and a9 = 120 is Common difference: [120  (32)]/8 = 11 nth or General Term of an Arithmetic Sequence an = a1 + (n  1)d where a1 is the first term of the sequence and d is the common difference. a32 = 32 + (31)*(11) = 32  341 = 373 @gahoolianowl
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