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anonymous

  • one year ago

For an angle Θ with the point (16, −30) on its terminating side, what is the value of cosine?

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  1. anonymous
    • one year ago
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    \(16\) over the hypotenuse of the triangle with one side \(16\) and the other \(30\)

  2. anonymous
    • one year ago
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    i.e. \[\frac{16}{\sqrt{16^2+30^2}}\] as a start

  3. anonymous
    • one year ago
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    You need to solve for c. a2+b2=c2

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  4. anonymous
    • one year ago
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    @PrincessHush nice picture!

  5. anonymous
    • one year ago
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    Thanks! (: @satellite73

  6. Directrix
    • one year ago
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    Doesn't theta in this case have one side on the x-axis? |dw:1444266733897:dw|

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  7. Directrix
    • one year ago
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    cos(theta) = adjacent side over hypotenuse

  8. anonymous
    • one year ago
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    g(x) = 4 sin(4x) − 3, what is the value of the y intercept?

  9. anonymous
    • one year ago
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    @Deadly_Roses

  10. anonymous
    • one year ago
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    cos(Θ) = x/r = x/sqrt(x^2 + y^2) = 16/sqrt[16^2 + (−30)^2] = 16/34 = 8/17.

  11. anonymous
    • one year ago
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    so 8/17?

  12. Deadly_Roses
    • one year ago
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    princess is correct, it would be 8/17

  13. anonymous
    • one year ago
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    okay, thanks

  14. anonymous
    • one year ago
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    rose, can you clarify the earlier comments for me? i don't quite understand what they were saying

  15. anonymous
    • one year ago
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    Yes @gahoolianowl it is 8/17 and I would help you step by step but unfortunately I have to go I hope @Deadly_Roses can help you with whatever you need or if she cant ill try to get you help if you would like met to.

  16. anonymous
    • one year ago
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    thank you for all of your help. it is very much appreciated. im sure rose will do wonderfully. she has yet to let me down with this stuff

  17. Directrix
    • one year ago
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    You'll need to learn these. See attachment.

  18. anonymous
    • one year ago
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    i haven't seen those since geometry 4 years ago 0.0 i forgot all about them

  19. anonymous
    • one year ago
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    What is the 32nd term of the arithmetic sequence where a1 = −32 and a9 = −120?

  20. anonymous
    • one year ago
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    The 32nd term of the arithmetic sequence where a1 = -32 and a9 = -120 is Common difference: [-120 - (-32)]/8 = -11 nth or General Term of an Arithmetic Sequence an = a1 + (n - 1)d where a1 is the first term of the sequence and d is the common difference. a32 = -32 + (31)*(-11) = -32 - 341 = -373 @gahoolianowl

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