Jhulian
  • Jhulian
got stuck... 2sin(squared) theta =1
Trigonometry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
kawii2004
  • kawii2004
okay
Jhulian
  • Jhulian
help me solve
kawii2004
  • kawii2004
umm wait

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Do you mean 2sin^2theta=1
Jhulian
  • Jhulian
yes
anonymous
  • anonymous
\[2 \sin ^2\theta=1,or~1-\cos 2\theta=1\] \[\cos 2\theta=0=\cos (2n+1)\frac{ \pi }{ 2 }\] \[2 \theta=\left( 2n+1 \right)\frac{ \pi }{ 2 },\theta=\left( 2n+1 \right)\frac{ \pi }{ 4 }\]
anonymous
  • anonymous
here n is an integer.
Jhulian
  • Jhulian
thanks
anonymous
  • anonymous
2sin²(θ) = 1 sin²(θ) = 1/2 sin(θ) = ± 1/√2 sin(θ) = ± (√2)/2 First case: sin(θ) = + (√2)/2 θ = π/4 θ = π - (π/4) = 3π/4 Second case: sin(θ) = - (√2)/2 θ = 2π - (π/4) = 7π/4 θ = π + (π/4) = 5π/4 → Solution = { π/4 ; 3π/4 ; 5π/4 ; 7π/4 }
Jhulian
  • Jhulian
Thanks princess!
anonymous
  • anonymous
yw
anonymous
  • anonymous
You are quite welcome @Jhulian if you no longer have any questions about this subject please do close the question. Thank you very much.(:

Looking for something else?

Not the answer you are looking for? Search for more explanations.