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anonymous

  • one year ago

How many solutions does the equation have? 2(2x+5)=4(x+3) A. one solution B. infinite solutions C. no solution

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  1. SolomonZelman
    • one year ago
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    2(2x+5)=4(x+3) 4x+10=4x+12

  2. SolomonZelman
    • one year ago
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    Is that true for any values of x?

  3. anonymous
    • one year ago
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    no solution?

  4. SolomonZelman
    • one year ago
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    Yes

  5. anonymous
    • one year ago
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    Thank You!

  6. SolomonZelman
    • one year ago
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    Yw !

  7. anonymous
    • one year ago
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    How many solutions does the equation have? a+5=1/5(5a+25) A. one solution B. infinite solutions C. no solution What about this one i think infinite solutions

  8. SolomonZelman
    • one year ago
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    \(\large\color{black}{ a+5=\frac{1}{5}(5a+25)}\) like this?

  9. anonymous
    • one year ago
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    yes

  10. SolomonZelman
    • one year ago
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    then you are correct - "infinte solutions" is the right answer.

  11. SolomonZelman
    • one year ago
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    Because when you expand the right side, you get: \(\large\color{black}{ a+5=\frac{1}{5}(5a+25)}\) \(\large\color{black}{ a+5=a+5}\) and that is true for any value of a.

  12. anonymous
    • one year ago
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    Thank you again!

  13. SolomonZelman
    • one year ago
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    You welcome, again! :)

  14. anonymous
    • one year ago
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    I have 3 more

  15. anonymous
    • one year ago
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    if you could check them

  16. SolomonZelman
    • one year ago
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    Alright...

  17. anonymous
    • one year ago
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    How many solutions does the equation have? 4x + 2(x-3)=8x + 12 A. one solution B. infinite solutions C. no solution

  18. SolomonZelman
    • one year ago
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    what did you choose?

  19. anonymous
    • one year ago
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    A?

  20. SolomonZelman
    • one year ago
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    Yes, correct!

  21. anonymous
    • one year ago
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    Thank You!!

  22. SolomonZelman
    • one year ago
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    yw

  23. anonymous
    • one year ago
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    Which expressions would complete this equation so that it has infinitely many solutions? 8 + 2(8x – 6) = Choose exactly two answers that are correct. A. 2(4x + 7) B. 9x – 10 C. 16x – 4 D. 4(4x – 1)

  24. SolomonZelman
    • one year ago
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    and your choice was?

  25. anonymous
    • one year ago
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    C and D?

  26. anonymous
    • one year ago
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    Or A and D?

  27. SolomonZelman
    • one year ago
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    8 + 2(8x – 6) = 8 + 16x – 12 = 16x – 4. ` same = same ` ----> ` 8 + 2(8x – 6) = 16x - 4 ` C is right

  28. anonymous
    • one year ago
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    So C and D?

  29. SolomonZelman
    • one year ago
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    8 + 2(8x – 6) = 8 + 4(4x – 3) = 8 + 4(4x – 1 - 2) = 8 + 4(4x – 1) + (-2)(4) = 8 + 4(4x – 1) -8 = 4(4x – 1) =

  30. SolomonZelman
    • one year ago
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    yes, C and D

  31. anonymous
    • one year ago
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    Thanks Again!!! I have one more

  32. SolomonZelman
    • one year ago
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    k

  33. anonymous
    • one year ago
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    What is the best way to classify each equation? Column AColumn B 1. 8x + 24=2(4x+12) 2. 5x + 18-x=2(2x+8) 3. 7(3x-2)=20x-13 4. 3x + 2(x-10)=5(x-4) A. identity B. contradiction C. neither @SolomonZelman

  34. SolomonZelman
    • one year ago
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    Can you write the Columns more clearly please?

  35. anonymous
    • one year ago
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    dont worry about the columns... Column A is with the long equations and Column B is A. identity B. contradiction C. neither

  36. SolomonZelman
    • one year ago
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    Column A Column B 1. 8x + 24=2(4x+12) 2. 5x + 18-x=2(2x+8) 3. 7(3x-2)=20x-13 4. 3x + 2(x-10)=5(x-4) like this?

  37. anonymous
    • one year ago
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    what you have underneath column B is suppose to be under Column A and under Column B is suppose to be this A. identity B. contradiction C. neither

  38. SolomonZelman
    • one year ago
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    Column A Column B 8x+24=2(4x+12) Identity 5x+18-x=2(2x+8) Contradiction 7(3x-2)=20x-13 Niether 3x+2(x-10)=5(x-4) like this?

  39. anonymous
    • one year ago
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    yes

  40. SolomonZelman
    • one year ago
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    `(When you expand 1st row, 1st column)` 8x+24=2(4x+12) \(\longrightarrow\) 8x+24=8x+24

  41. SolomonZelman
    • one year ago
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    `(Expand 2nd row, 1st column)` 5x+18-x=2(2x+8) \(\longrightarrow\) 5x+18-x=4x+16 `(Subtract x from 5x: 5x-x=4x)` 5x+18-x=4x+16 \(\longrightarrow\) 4x+18=4x+16

  42. SolomonZelman
    • one year ago
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    So at this point you should be able to tell me whether A is an *identity* (true for all values of x), a *contradiction* (true for NO values of x - i.e. always false) OR *Niether* (not contradition or identity - i.e. has 1 solution)

  43. SolomonZelman
    • one year ago
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    `(Expand 3rd row, 1st column)` 7(3x-2)=20x-13 \(\longrightarrow\) 21x-14=20x-13 `(Subtract 20x from both sides)` 21x-14=20x-13 \(\longrightarrow\) x-14=13 `(Add 14 to both sides)` x-14=13 \(\longrightarrow\) x=27 (and this is Niether)

  44. SolomonZelman
    • one year ago
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    `(Expand 4th row, 1st column)` 3x+2(x-10)=5(x-4) \(\longrightarrow\) 3x+2x-20=5x-20 `(Add like terms on the left side)` 3x+2x-20=5x-20 \(\longrightarrow\) 5x-20=5x-20 Can you identify this one as either: *identity*, *contradiction*, or *Neither*

  45. anonymous
    • one year ago
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    sorry I had to leave but im back @SolomonZelman

  46. SolomonZelman
    • one year ago
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    Ok, read over my posts, please. This should clarify every thing....

  47. anonymous
    • one year ago
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    ok

  48. anonymous
    • one year ago
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    so 1.A 2.B. 3.C 4.A?

  49. SolomonZelman
    • one year ago
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    yes, Identity Contradition Neither Identity *CORRECT!*

  50. anonymous
    • one year ago
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    THANK YOU!!!!!!!

  51. SolomonZelman
    • one year ago
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    Anytime:)

  52. anonymous
    • one year ago
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    I got 100%

  53. SolomonZelman
    • one year ago
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    Nice to hear that:)

  54. SolomonZelman
    • one year ago
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    have a good night!

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