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cooltowl
 one year ago
How many chlorine atoms are present in 25.3 g of the compound?
cooltowl
 one year ago
How many chlorine atoms are present in 25.3 g of the compound?

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matt101
 one year ago
Best ResponseYou've already chosen the best response.1What compound are you talking about?

matt101
 one year ago
Best ResponseYou've already chosen the best response.1We want to know how many Cl atoms there are. When we're looking for a number, always convert to moles! We have the mass of CCl4, and we can find moles by dividing the mass by the molar mass of CCl4, which is 154 g/mol. moles of CCl4 = 25.3 g / 154 g/mol = 0.1643 mol Each molecules of CCl4 contains 4 atoms of Cl, so for however many moles of CCl4 we have, there are FOUR times as many moles of Cl  in this case, 0.1643 x 4 = 0.6572 mol. Now we want to know the number of ATOMS of Cl. We can go from moles to number of atoms by multiplying moles by Avogadro's number: 6.022 x 10^23 atoms of Cl = 0.6572 mol x 6.022 x 10^23 = 3.958 x 10^23 atoms Does that make sense?

cooltowl
 one year ago
Best ResponseYou've already chosen the best response.0That makes perfect sense. Thank you so much for the step by step explanation:)
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