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cooltowl

  • one year ago

How many chlorine atoms are present in 25.3 g of the compound?

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  1. cooltowl
    • one year ago
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    @Shalante

  2. cooltowl
    • one year ago
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    @matt101

  3. matt101
    • one year ago
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    What compound are you talking about?

  4. cooltowl
    • one year ago
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    CCl4

  5. matt101
    • one year ago
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    We want to know how many Cl atoms there are. When we're looking for a number, always convert to moles! We have the mass of CCl4, and we can find moles by dividing the mass by the molar mass of CCl4, which is 154 g/mol. moles of CCl4 = 25.3 g / 154 g/mol = 0.1643 mol Each molecules of CCl4 contains 4 atoms of Cl, so for however many moles of CCl4 we have, there are FOUR times as many moles of Cl - in this case, 0.1643 x 4 = 0.6572 mol. Now we want to know the number of ATOMS of Cl. We can go from moles to number of atoms by multiplying moles by Avogadro's number: 6.022 x 10^23 atoms of Cl = 0.6572 mol x 6.022 x 10^23 = 3.958 x 10^23 atoms Does that make sense?

  6. cooltowl
    • one year ago
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    That makes perfect sense. Thank you so much for the step by step explanation:)

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