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dan815

  • one year ago

Graph Theory Oberwolfach problem and this Theorem http://prntscr.com/8oz0bm

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  1. dan815
    • one year ago
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    |dw:1444275641548:dw|

  2. dan815
    • one year ago
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    @Empty

  3. Empty
    • one year ago
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    |dw:1444275833904:dw|

  4. dan815
    • one year ago
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    i thought they all gotta be connected

  5. Empty
    • one year ago
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    No you just have to have the same number of vertices to be a factor, and all the vertices must have degree 2

  6. dan815
    • one year ago
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    what do u mean same number of vertices, like your subgraphs of 2 factors should all ahve same number of vertices?

  7. Empty
    • one year ago
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    Yeah so to be a k-factor it just means remove edges so that each vertex has degree k.

  8. dan815
    • one year ago
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    okay gotchaa!!

  9. dan815
    • one year ago
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    alright lets go read on this oberwachj problem

  10. dan815
    • one year ago
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    http://prntscr.com/8oz3nc

  11. dan815
    • one year ago
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    we can do a practice problem that is like an intro to this

  12. dan815
    • one year ago
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    http://prntscr.com/8oz41q

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spraguer (Moderator)
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