anonymous
  • anonymous
A volleyball is thrown up in the air with initial velocity of 8.2m/s. How long does it take the ball to reach maximum height? help please!
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
zephyr141
  • zephyr141
do you know the kinematic equations?
zephyr141
  • zephyr141
if you don't just google them.
anonymous
  • anonymous
well i was given 3 to choose from. and i know im looking for the time. so im going to assume i have to use either, g=vf-vi/ t or y= vi(t)+1/2 (g) (t)^2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zephyr141
  • zephyr141
\[1:d=v_0t+\frac{1}{2}at^2\]\[2:v^2=v_0^2+2ad\]\[3:v=v_0+at\]\[4:d=\frac{v_0+v}{2}t\]
zephyr141
  • zephyr141
i would use number 3.
anonymous
  • anonymous
oh then idk what i just gave you because thats like completely different but ok so how would i get t by itself
zephyr141
  • zephyr141
\[0=8.2+(-9.8)t\]\[-8.2=(-9.8)t\]\[\frac{-8.2}{-9.8}=t\]\[0.84s=t\]
zephyr141
  • zephyr141
subtract 8.2 from both sides. then divide both sides by (-9.8) to isolate t.
zephyr141
  • zephyr141
the first equation you gave me looks a lot like equation 4 that i gave you.
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
so then how do i know what the total time was that the ball was in the air?
zephyr141
  • zephyr141
well we found the time it took to get up to it's max height. assuming that nothing changes in it's descent then it should be the same amount of time on the way back down. |dw:1444277213628:dw|
zephyr141
  • zephyr141
so you can figure that one out. you can do it!
anonymous
  • anonymous
lol so i just add them then? right?
zephyr141
  • zephyr141
yep. that's the total time in flight. of course if the final resting point is any number of feet/meters or whatever measurement lesser or greater than it's original values then the problem gets a little harder.
anonymous
  • anonymous
ahhhh i got you now. thanks!
zephyr141
  • zephyr141
don't forget to medal. lol. good luck on any future problems.

Looking for something else?

Not the answer you are looking for? Search for more explanations.