anonymous
  • anonymous
A volleyball is thrown up in the air with initial velocity of 8.2m/s. what is the maximum height reached?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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zephyr141
  • zephyr141
use the kinematic equations. looks like it's the same ball with the same initial velocity. so that means we can use the time we found in the last question to find the maximum height achieved. now remember that at it's highest point the final velocity in the y direction will be 0 so knowing that let's look at the kinematic equations again and pick the best equation that best fits this problem.
zephyr141
  • zephyr141
matter in fact we can use this one\[d=v_0t+\frac{1}{2}at^2\]
zephyr141
  • zephyr141
i think the time we found was 0.84 seconds.

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anonymous
  • anonymous
well my teacher said not to use the same time for this cause it'll give me the wrong answer
zephyr141
  • zephyr141
are you sure? because the time isn't going to change if you solve for time for this equation. i just checked and the velocities are the same in both questions and since gravity isn't changing it has to be the same time.
anonymous
  • anonymous
i didnt understand her reasoning but i think thats whats throwing me off.
zephyr141
  • zephyr141
ok lets leave time out then. use this equation. it doesn't need time.\[v^2=v_0^2+2ad\]
zephyr141
  • zephyr141
isolate d in the equation first.
anonymous
  • anonymous
alright
zephyr141
  • zephyr141
you should get \[d=\frac{v^2-v_0^2}{2a}\]and now just plug in your known values. v0=8.2 m/s v=0 a=-9.8
anonymous
  • anonymous
okay. so i got -8.2/ -19.6??
zephyr141
  • zephyr141
\[d=\frac{0-(8.2)^2}{-19.6}=\frac{-67.24}{-19.6}=3.4306m\] or 3.4 meters. which is the same if we used time. so i don't really know why your teacher told you not to use time. maybe to solve it using a different equation.
anonymous
  • anonymous
oh man i didnt square them. yah probably idk ill ask her about it, thanks! again lol
zephyr141
  • zephyr141
lol no problem.

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