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anonymous

  • one year ago

x^6-64 facotr as a diffrence of square and cube please help

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  1. anonymous
    • one year ago
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    is it -4(x+6) . my firend got that answer. didnt tell me how to do it tho

  2. Directrix
    • one year ago
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    x^6-64 = (x^3)^2 - (8)^2 = ( x^3 + 8) * (x^3 - 8) That is the factorization into 2 squares.

  3. Directrix
    • one year ago
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    >>is it -4(x+6) NO

  4. Directrix
    • one year ago
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    Factor x^6-64 as difference of 2 cubes. Factoring pattern is attached.

  5. anonymous
    • one year ago
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    im going to try the cube and see what i get

  6. anonymous
    • one year ago
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    x--4(x^3+4x+16)

  7. anonymous
    • one year ago
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    i think

  8. Directrix
    • one year ago
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    x^6-64 = [ (x^2)^3 - (4)^3) ] = [ x^2 - 4 ] * [ (x^2)^2 + (x^2)*4) + (-4)^2 ]

  9. anonymous
    • one year ago
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    (x-4)(x^2+4x+4^2)

  10. Directrix
    • one year ago
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    [ x^2 - 4 ] * [ (x^2)^2 + (x^2)*4) + (-4)^2 ] = (x^2 -4) (x^4 + 4x^2 + 16)

  11. anonymous
    • one year ago
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    okay i see what i did wrong . i dont know where i got a 3 from. thank you for the help . both of you

  12. Directrix
    • one year ago
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    I am uncertain about the instructions. Taking it from the top: x^6-64 = (x^3)^2 - (8)^2 = ( x^3 + 8) * (x^3 - 8) = (x + 2) ( x^2 -2x + 4) (x - 2) (x^2 + 2x + 4)

  13. Directrix
    • one year ago
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    You are welcome.

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