g(x)= 4^x+3 +2 Halp Halp :( will medal

- Melissa_Something

g(x)= 4^x+3 +2 Halp Halp :( will medal

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- schrodinger

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- zepdrix

\[\large\rm g(x)=4^{x+3}+2\]What do we have to do with this function? :o

- Melissa_Something

Graph it :( We have to pick 3 points but I chose 1 and got like 258

- Melissa_Something

My graph only goes to 6... on the worksheet that is -_____-

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## More answers

- zepdrix

|dw:1444279384850:dw|It's an exponential, so it looks something like this :U

- Melissa_Something

wait its not exponential?? lol ugh

- zepdrix

Oh you're picking points and stuff? :)
Ok ok hmm

- Melissa_Something

Yeah I mean it would look like that though. I tried -1 and got 18 which is still a big number :(

- zepdrix

Ya, you don't want really big numbers.
So you would like to make the `exponent` as close to zero as possible.
So you want this x+3 to be somewhat small.
How bout x=-3?

- zepdrix

18 isn't big, simmer down :) lol

- Melissa_Something

Apparently for the graph it is lol

- zepdrix

\(\large\rm (-3,?)\) what do you get for your y when plug in -3 for x?

- Melissa_Something

Okay for -3 = 6 :) much better

- zepdrix

Hmm that doesn't sound right.

- Melissa_Something

No?

- zepdrix

\[\large\rm g(-3)=4^{-3+3}+2\]\[\large\rm g(-3)=4^{0}+2\]4^0 is? :o

- Melissa_Something

Oh, its 1. Fantastic Ima fail this lol :/

- zepdrix

\(\large\rm (-3,3)\) mmm ok good that gives us one point :)
How about choosing another value that is really close by, like umm... -2?

- Melissa_Something

Okay :) Lemme do it

- Melissa_Something

its 6!!!!

- zepdrix

\(\large\rm (-2,6)\)
Ahh there's that 6 :) lol

- zepdrix

If x=-1 is giving you a value that is too big,
then you could try going the other direction I suppose,
x=-4

- Melissa_Something

What if we do -4? Since -1 = 18 -___-

- Melissa_Something

Okay doing it now :)

- Melissa_Something

it comes out at 2.25

- zepdrix

\(\large\rm (-4,2.25)\)
Yay good job \c:/

- zepdrix

Graph em.. connect the dots :p go .. do it

- Melissa_Something

Lol it looks kinda weird but I'll take it! It must be right.

- Melissa_Something

What will be thr asymptote? :o

- zepdrix

The normal asymptote for an exponential function will be the x-axis, which is y=0.
The +2 on the end of our function is a vertical shift up 2 units.
So hmm.. what will that do? :)

- Melissa_Something

Oh no, theres more?!?! :(

- Melissa_Something

y=2.25?? @zepdrix

- Melissa_Something

Lol I knew you were gonna click on that other question, I clicked on it too. Great minds think alike :)

- zepdrix

The +2 is shifting `everything` up by 2.
So it shifts the asymptote up by 2.
So instead of having an asymptote at y=0,
you'll have an asymptote at y=2.

- Melissa_Something

Thank you, thank you!!!!!! Good luck helping that guy! <3 Youre awesome

- zepdrix

:3

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