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anonymous

  • one year ago

Simplify each expression. Use positive exponents. M^3 n^-6 p^0 show work

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  1. zepdrix
    • one year ago
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    \[\large\rm m^3\color{orangered}{n^{-6}}\color{royalblue}{p^0}\]To deal with the orange part, we'll use this rule:\[\large\rm \color{orangered}{x^{-a}=\frac{1}{x^a}}\]We flip it! And the exponent becomes positive. Do deal with the blue part, Anything to the 0 power is 1. You can think of it like... p^1 is p. So p^0 is dividing p by itself.

  2. zepdrix
    • one year ago
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    \[\large\rm m^3\color{orangered}{n^{-6}}\color{royalblue}{p^0}=m^3\color{orangered}{n^{-6}}\color{royalblue}{1}\]So that rule takes care of the blue part. Do you understand how the orange rule helps us? :D

  3. anonymous
    • one year ago
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    I'm lost.. I seriously suck at algebra. I've been stuck on this question for 7 months

  4. zepdrix
    • one year ago
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    7 months?? 0_o oh boy

  5. zepdrix
    • one year ago
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    Anyway, exponent rule tells us to flip it, and change the exponent to positive,\[\large\rm m^3\color{orangered}{n^{-6}}\color{royalblue}{p^0}=m^3\color{orangered}{\frac{1}{n^6}}\color{royalblue}{1}\]

  6. anonymous
    • one year ago
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    Hold up. M^3 N^-6 P^0 M^3 x 1/n^6 =m^3/n^6

  7. anonymous
    • one year ago
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    What now o.o

  8. zepdrix
    • one year ago
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    nothing else :o

  9. anonymous
    • one year ago
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    You mean.... I'm finally done O.O

  10. zepdrix
    • one year ago
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    lol ya :U

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