A community for students.
Here's the question you clicked on:
 0 viewing
leozap1
 one year ago
Anyone know of a site that could answer these types of questions? Mathway won't answer these types. *Fan & Medal*
Let f(x) = 5x  4 and g(x) = 6x  7. Find f(x) + g(x)
leozap1
 one year ago
Anyone know of a site that could answer these types of questions? Mathway won't answer these types. *Fan & Medal* Let f(x) = 5x  4 and g(x) = 6x  7. Find f(x) + g(x)

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://www.algebra.com/algebra/homework/Functions/Functions.faq.question.824363.html

leozap1
 one year ago
Best ResponseYou've already chosen the best response.1That's a different question, but I'll ask on the site. Thanks.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \color{royalblue}{f(x) = 5x  4} \quad\text{and}\quad \color{orangered}{g(x) = 6x  7}\]Then,\[\large\rm \color{royalblue}{f(x)}+\color{orangered}{g(x)}=\color{royalblue}{5x4}+\color{orangered}{6x7}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Combine liketerms: 5x + 6x = ? 4 7 = ?

leozap1
 one year ago
Best ResponseYou've already chosen the best response.15x + 6x = 1x so just x. 4  7 = 11. So the answer is x  11?

leozap1
 one year ago
Best ResponseYou've already chosen the best response.1Could you help me with some more? f(x) = 3x+2 and g(x) = 6x  7. I tried working it out and I got 9x5, but that's not an answer choice.

leozap1
 one year ago
Best ResponseYou've already chosen the best response.1It was negative not positive.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.