227 229 271 317 349 You can use all the types of methods to try and get the answer, but you MUST use 1997, and keep it in that order no matter what. Please help, too hard 4 me...

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227 229 271 317 349 You can use all the types of methods to try and get the answer, but you MUST use 1997, and keep it in that order no matter what. Please help, too hard 4 me...

Mathematics
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Other answers:

What is the question?
You have to make those numbers by using 1997
you can't rearrange them, but you can use anything you want to make it the number. You can use powers, square roots, etc.
I can't get it at all, so I was wondering if anyone else could help me with this xD
interesting :)
Can't do it xD
Closest I got was 220
can we rearrange the number 1,9,9,7?
nope xD
it has to stay in that specific order
(1 + 9) x 9 x √7 = 238.1
SO CLOSE
this is hard, how did you get 220?
(19+9)+7^2
(1 + √9) x 9 x 7 = 252
(19 x 9) + 7^2 = 220
yep, thats what I did xD
closest thing I got xD
(1 x 9 x 9) + √7 = 214.3
:o
\[\sqrt{\sqrt{1\times 9^9\times7}}=228.2\]
wow, thats really close /:
So annoying... this stupid assignment.
can you use powers of numbers other than 1,9,9,7?
if you mean, can you square it or "double it" yes you can
but 1997 has to stay in place/ keep the same structure.
so you can use 1997 as many times as you want but it keeps that structure, like 1*9*9*7*1*9*9....etc?
oh... no thats not usable xD
so you can only use 1997 once then?
mhmm
(1 x 9 x 9) + √7 = 214.3
but wouldn't it be defeating the purpose if you use powers of 3 then? even tho you are multiplying it 3 times... your using a number not in that set..
probs over thinking it.
uhhh xD
I dunno xD Its hard just trying to do it the legit way xD
227 is a prime number, so I suppose the manipulation of the numbers you have should reflect that... I'm struggling quite a bit as well, but maybe you should work backwards? add 1, 9 or 7 to your target number and try to factorize it to get hints on how to create it..
:o thats a good idea, i'll try that now xD
I just got 226 :P
gg no re jade is a genius
can we do something like this- \[1 \times \sqrt{9},\sqrt[\infty]{9},7 =317\]?
yep
so 317 is done :)
:o thank you xD
But I don't get how it becomes 317 xD
\[1 \times \sqrt{9}=1 \times 3=3\]\[\sqrt[\infty]{9}=1\]\[7=7\] joining all :) 317
:o
thank you for your explanation xD
np (:
and thank you jade, i'll make sure to use your methods :D
@imqwerty You can join the numbers? don't you have to add or multiply?
OH
idk? @Epicteatime said yes so i did it :)
Yeah, you have to add them or multiply them to get the actual number, sorry Jade I didnt see how you got it xD
not jade, imqwerty
1×9√,9√∞,7=317
ah, so no joining then, that would have made it easier. :c
2^2 • 3 • 19 = 228 - (227 +1) 2 • 113 = 226 = (227-1) 22 • 5 • 11 = 220 = (227 - 7) 2 • 32 • 13 = 234 = (227 +7) 22 • 59 = 236 = (227 +9) 2 • 109 = 218 = (227 - 9)
yeah, it would have
lauren, thats not how you do it xD Thanks for your effort though :D
I'm sure this is actually a simple question at it's heart, I doubt we need fancy, doctorate level thesis' on how this could work. The numbers we have are 1 , 9 , 9 , 7 , they have to be dealt with in that order, but they can be subtracted and added to each other, as well as divided and multiplied. We can use any number we wish when "doubling" or calculating to the power, right @epicteatime ?
@Epicteatime I got ONE answer. \[1 * 9^{2.5} - 9 - 7 = 227 \]
sorry, I went to eat dinner xD Im back now tho :D
and thank you for answering one xD
sadly there's still like, 4 :P
@Epicteatime Hope you enjoyed dinner haha, I know, but once one goes down, surely the rest should be easier? XD
maybe, maybe
xD
which one are you doing jade?
I'm trying to do the second one now, it's only a difference of 2 so...
alright, i'll do 271 then :D
holy crap...
I Just got 271
but I still need to do something with 7 xD
So, I need to subtract 14 from \[9^{2.5}\] in order to get 229. How can I make 14? --- Also, congrats! I'm sure you can turn the 7 into a 0 somehow...
so which ones do you have left? haha
229 271 317 349
those :3
ahh okiee
yush :3
I GOT 271!!!!
oh wait...
1997-99-1/7
uhh
hmmm....
1-99/7=271? xD
can we use the numbers 1, 9, 9 and 7 as many times as we'd like?
nope xD
sadly xD
damn ahahha
but can we rearrange stuff to make like 99 and 17 and stuff?
99 yes, 17 no xD
you have to keep 1997 in that order
OH i think I'm finally clear on the rules lololol
lol xD well try your best :D
so slow xD haha, okay
damn
I got 318
.7
so basically 319 xD
you got 317?
can't you subtract 7^0 to get 317?
:o
wait a sec :3
1 x 9^2.6+9+7
just putting that there
I did what you told me jade, and I got 311 xD
whoops haha
we can't do 199 + (19 x (9 - 7)) - (7 + 1) = 229 can we? :/
don't think so firekat :c
ah no xD sorry m80 :P
hahah damn
btw what year is this? this is torture lol I'd hate getting an assignment like this
year 10 xD
omg seriously, our assignments were so easy in comparison
hahahaha we'd get like quadratics 90% of the time
Considering I just started year 11 it is kind of embarrassing I can't solve this lmao
lol Im a first year and can't solve it so :$
but we need to carry on, we can do this!
YES
BELIEVE IN YOUR DREAMS!
HAHAHA
xD
I GOT IT
229!
yayayayyayay!!
1*(99+7^2.5)
good job!
that SHOULD work
you round it so you get 229
but how did you get 2.5?
So you're allowed to combine numbers?
Yeah, just keep the order
2.5? its the power
why did i not know this also are you sure you can just round it off?
ohh we can use any power?
pretty sure.
and yes, you can xD
ahhh okayyyy
you just can't change the number, or change its position
ah oka cool
:3
\[1 * (9 - \sqrt9) + 7 ^3 = 349\]
:o
NICE :D
YAS
woww niceee
so 229 271 317 left?
I got 229
ah okay
we only got 2 more left
317 and 349
I got 349 : o
yep :3
MVP
xD
so 271 + 317 ?
?
so if we can use any powers and round off, would \[1 \times 9^{5/2} + 9^{3/2} \times 7^{0.026}\] work? cus it gives 271.401..
so if we can use any powers and round off, would \[1 \times 9^{5/2} + 9^{3/2} \times 7^{0.026}\] work? cus it gives 271.401..
uhhh... yeah I guess xD
You said we have two left, you solved 229 , and I solved 227 + 349 so the other two are 271 and 317
ohh thats what you meant xD yes, thats what we have left :D
Very close FireKat! Although I'm wary of decimals, if 2 don't have decimals should others?
actually its 349 and 317
oh
wait no
\[1 * (9 - \sqrt9) + 7^3 \] = 349 \[1 * 9^{2.5} - 9 - 7\] = 227
271 and 317
yes
is what we have left.
i got 319 again xD
What is your equation?
1x(9^2.5+9)+7
Isn't that 259?
no idea xD
9^2.5 + 9 + 7 = 259
damn, got 270, and gg :D
1+(9.9^3.29)/7
oh wait I got it
1+(9.9^3.291)/7 :P
271.1
now we only have 317
very close
Unfortunately I can't stay any more, I have a lot of work myself. :c Please message me with your results. ;u;
lol alright xD Thanks a lot for your help fwendo :D
gg done :D Thanks everyone for participating :D

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