## Epicteatime one year ago 227 229 271 317 349 You can use all the types of methods to try and get the answer, but you MUST use 1997, and keep it in that order no matter what. Please help, too hard 4 me...

1. epicteatime

@whpalmer4

2. epicteatime

@ParthKohli

3. epicteatime

@Luigi0210

4. epicteatime

@dan815

5. epicteatime

@UnkleRhaukus

6. UnkleRhaukus

What is the question?

7. epicteatime

You have to make those numbers by using 1997

8. epicteatime

you can't rearrange them, but you can use anything you want to make it the number. You can use powers, square roots, etc.

9. epicteatime

I can't get it at all, so I was wondering if anyone else could help me with this xD

10. imqwerty

interesting :)

11. epicteatime

Can't do it xD

12. epicteatime

Closest I got was 220

13. imqwerty

can we rearrange the number 1,9,9,7?

14. epicteatime

nope xD

15. epicteatime

it has to stay in that specific order

16. UnkleRhaukus

(1 + 9) x 9 x √7 = 238.1

17. epicteatime

SO CLOSE

18. UnkleRhaukus

this is hard, how did you get 220?

19. epicteatime

(19+9)+7^2

20. UnkleRhaukus

(1 + √9) x 9 x 7 = 252

21. UnkleRhaukus

(19 x 9) + 7^2 = 220

22. epicteatime

yep, thats what I did xD

23. epicteatime

closest thing I got xD

24. UnkleRhaukus

(1 x 9 x 9) + √7 = 214.3

25. epicteatime

:o

26. UnkleRhaukus

$\sqrt{\sqrt{1\times 9^9\times7}}=228.2$

27. epicteatime

wow, thats really close /:

28. epicteatime

So annoying... this stupid assignment.

29. anonymous

can you use powers of numbers other than 1,9,9,7?

30. epicteatime

if you mean, can you square it or "double it" yes you can

31. epicteatime

but 1997 has to stay in place/ keep the same structure.

32. anonymous

so you can use 1997 as many times as you want but it keeps that structure, like 1*9*9*7*1*9*9....etc?

33. epicteatime

oh... no thats not usable xD

34. anonymous

so you can only use 1997 once then?

35. epicteatime

mhmm

36. anonymous

(1 x 9 x 9) + √7 = 214.3

37. anonymous

but wouldn't it be defeating the purpose if you use powers of 3 then? even tho you are multiplying it 3 times... your using a number not in that set..

38. anonymous

probs over thinking it.

39. epicteatime

uhhh xD

40. epicteatime

I dunno xD Its hard just trying to do it the legit way xD

227 is a prime number, so I suppose the manipulation of the numbers you have should reflect that... I'm struggling quite a bit as well, but maybe you should work backwards? add 1, 9 or 7 to your target number and try to factorize it to get hints on how to create it..

42. epicteatime

:o thats a good idea, i'll try that now xD

43. epicteatime

I just got 226 :P

44. epicteatime

gg no re jade is a genius

45. imqwerty

can we do something like this- $1 \times \sqrt{9},\sqrt[\infty]{9},7 =317$?

46. epicteatime

yep

47. imqwerty

so 317 is done :)

48. epicteatime

:o thank you xD

49. epicteatime

But I don't get how it becomes 317 xD

50. imqwerty

$1 \times \sqrt{9}=1 \times 3=3$$\sqrt[\infty]{9}=1$$7=7$ joining all :) 317

51. epicteatime

:o

52. epicteatime

thank you for your explanation xD

53. imqwerty

np (:

54. epicteatime

and thank you jade, i'll make sure to use your methods :D

@imqwerty You can join the numbers? don't you have to add or multiply?

56. epicteatime

OH

57. imqwerty

idk? @Epicteatime said yes so i did it :)

58. epicteatime

Yeah, you have to add them or multiply them to get the actual number, sorry Jade I didnt see how you got it xD

59. epicteatime

60. anonymous

1×9√,9√∞,7=317

ah, so no joining then, that would have made it easier. :c

62. anonymous

2^2 • 3 • 19 = 228 - (227 +1) 2 • 113 = 226 = (227-1) 22 • 5 • 11 = 220 = (227 - 7) 2 • 32 • 13 = 234 = (227 +7) 22 • 59 = 236 = (227 +9) 2 • 109 = 218 = (227 - 9)

63. epicteatime

yeah, it would have

64. epicteatime

lauren, thats not how you do it xD Thanks for your effort though :D

I'm sure this is actually a simple question at it's heart, I doubt we need fancy, doctorate level thesis' on how this could work. The numbers we have are 1 , 9 , 9 , 7 , they have to be dealt with in that order, but they can be subtracted and added to each other, as well as divided and multiplied. We can use any number we wish when "doubling" or calculating to the power, right @epicteatime ?

@Epicteatime I got ONE answer. $1 * 9^{2.5} - 9 - 7 = 227$

67. epicteatime

sorry, I went to eat dinner xD Im back now tho :D

68. epicteatime

and thank you for answering one xD

69. epicteatime

sadly there's still like, 4 :P

@Epicteatime Hope you enjoyed dinner haha, I know, but once one goes down, surely the rest should be easier? XD

71. epicteatime

maybe, maybe

72. epicteatime

xD

73. epicteatime

which one are you doing jade?

I'm trying to do the second one now, it's only a difference of 2 so...

75. epicteatime

alright, i'll do 271 then :D

76. epicteatime

holy crap...

77. epicteatime

I Just got 271

78. epicteatime

but I still need to do something with 7 xD

So, I need to subtract 14 from $9^{2.5}$ in order to get 229. How can I make 14? --- Also, congrats! I'm sure you can turn the 7 into a 0 somehow...

80. FireKat97

so which ones do you have left? haha

81. epicteatime

229 271 317 349

82. epicteatime

those :3

83. FireKat97

ahh okiee

84. epicteatime

yush :3

85. epicteatime

I GOT 271!!!!

86. epicteatime

oh wait...

87. epicteatime

1997-99-1/7

88. epicteatime

uhh

89. epicteatime

hmmm....

90. epicteatime

1-99/7=271? xD

91. FireKat97

can we use the numbers 1, 9, 9 and 7 as many times as we'd like?

92. epicteatime

nope xD

93. epicteatime

94. FireKat97

damn ahahha

95. FireKat97

but can we rearrange stuff to make like 99 and 17 and stuff?

96. epicteatime

99 yes, 17 no xD

97. epicteatime

you have to keep 1997 in that order

98. FireKat97

OH i think I'm finally clear on the rules lololol

99. epicteatime

lol xD well try your best :D

100. FireKat97

so slow xD haha, okay

101. epicteatime

damn

102. epicteatime

I got 318

103. epicteatime

.7

104. epicteatime

so basically 319 xD

you got 317?

can't you subtract 7^0 to get 317?

107. epicteatime

:o

108. epicteatime

wait a sec :3

109. epicteatime

1 x 9^2.6+9+7

110. epicteatime

just putting that there

111. epicteatime

I did what you told me jade, and I got 311 xD

whoops haha

113. FireKat97

we can't do 199 + (19 x (9 - 7)) - (7 + 1) = 229 can we? :/

don't think so firekat :c

115. epicteatime

ah no xD sorry m80 :P

116. FireKat97

hahah damn

117. FireKat97

btw what year is this? this is torture lol I'd hate getting an assignment like this

118. epicteatime

year 10 xD

119. FireKat97

omg seriously, our assignments were so easy in comparison

120. FireKat97

hahahaha we'd get like quadratics 90% of the time

Considering I just started year 11 it is kind of embarrassing I can't solve this lmao

122. FireKat97

lol Im a first year and can't solve it so :\$

but we need to carry on, we can do this!

124. epicteatime

YES

125. epicteatime

126. FireKat97

HAHAHA

127. epicteatime

xD

128. epicteatime

I GOT IT

129. epicteatime

229!

130. FireKat97

yayayayyayay!!

131. epicteatime

1*(99+7^2.5)

132. FireKat97

good job!

133. epicteatime

that SHOULD work

134. epicteatime

you round it so you get 229

135. FireKat97

but how did you get 2.5?

So you're allowed to combine numbers?

137. epicteatime

Yeah, just keep the order

138. epicteatime

2.5? its the power

why did i not know this also are you sure you can just round it off?

140. FireKat97

ohh we can use any power?

141. epicteatime

pretty sure.

142. epicteatime

and yes, you can xD

143. FireKat97

ahhh okayyyy

144. epicteatime

you just can't change the number, or change its position

145. FireKat97

ah oka cool

146. epicteatime

:3

$1 * (9 - \sqrt9) + 7 ^3 = 349$

148. epicteatime

:o

149. epicteatime

NICE :D

YAS

151. FireKat97

woww niceee

so 229 271 317 left?

153. epicteatime

I got 229

ah okay

155. epicteatime

we only got 2 more left

156. epicteatime

317 and 349

I got 349 : o

158. epicteatime

yep :3

159. epicteatime

MVP

160. epicteatime

xD

so 271 + 317 ?

162. epicteatime

?

163. FireKat97

so if we can use any powers and round off, would $1 \times 9^{5/2} + 9^{3/2} \times 7^{0.026}$ work? cus it gives 271.401..

164. FireKat97

so if we can use any powers and round off, would $1 \times 9^{5/2} + 9^{3/2} \times 7^{0.026}$ work? cus it gives 271.401..

165. epicteatime

uhhh... yeah I guess xD

You said we have two left, you solved 229 , and I solved 227 + 349 so the other two are 271 and 317

167. epicteatime

ohh thats what you meant xD yes, thats what we have left :D

Very close FireKat! Although I'm wary of decimals, if 2 don't have decimals should others?

169. epicteatime

actually its 349 and 317

170. FireKat97

oh

171. epicteatime

wait no

$1 * (9 - \sqrt9) + 7^3$ = 349 $1 * 9^{2.5} - 9 - 7$ = 227

173. epicteatime

271 and 317

yes

175. epicteatime

is what we have left.

176. epicteatime

i got 319 again xD

178. epicteatime

1x(9^2.5+9)+7

Isn't that 259?

180. epicteatime

no idea xD

9^2.5 + 9 + 7 = 259

182. epicteatime

damn, got 270, and gg :D

183. epicteatime

1+(9.9^3.29)/7

184. epicteatime

oh wait I got it

185. epicteatime

1+(9.9^3.291)/7 :P

186. epicteatime

271.1

187. epicteatime

now we only have 317

very close

Unfortunately I can't stay any more, I have a lot of work myself. :c Please message me with your results. ;u;

190. epicteatime

lol alright xD Thanks a lot for your help fwendo :D

191. epicteatime

gg done :D Thanks everyone for participating :D