## anonymous one year ago 227 229 271 317 349 You can use all the types of methods to try and get the answer, but you MUST use 1997, and keep it in that order no matter what. Please help, too hard 4 me...

1. anonymous

@whpalmer4

2. anonymous

@ParthKohli

3. anonymous

@Luigi0210

4. anonymous

@dan815

5. anonymous

@UnkleRhaukus

6. UnkleRhaukus

What is the question?

7. anonymous

You have to make those numbers by using 1997

8. anonymous

you can't rearrange them, but you can use anything you want to make it the number. You can use powers, square roots, etc.

9. anonymous

I can't get it at all, so I was wondering if anyone else could help me with this xD

10. imqwerty

interesting :)

11. anonymous

Can't do it xD

12. anonymous

Closest I got was 220

13. imqwerty

can we rearrange the number 1,9,9,7?

14. anonymous

nope xD

15. anonymous

it has to stay in that specific order

16. UnkleRhaukus

(1 + 9) x 9 x √7 = 238.1

17. anonymous

SO CLOSE

18. UnkleRhaukus

this is hard, how did you get 220?

19. anonymous

(19+9)+7^2

20. UnkleRhaukus

(1 + √9) x 9 x 7 = 252

21. UnkleRhaukus

(19 x 9) + 7^2 = 220

22. anonymous

yep, thats what I did xD

23. anonymous

closest thing I got xD

24. UnkleRhaukus

(1 x 9 x 9) + √7 = 214.3

25. anonymous

:o

26. UnkleRhaukus

$\sqrt{\sqrt{1\times 9^9\times7}}=228.2$

27. anonymous

wow, thats really close /:

28. anonymous

So annoying... this stupid assignment.

29. anonymous

can you use powers of numbers other than 1,9,9,7?

30. anonymous

if you mean, can you square it or "double it" yes you can

31. anonymous

but 1997 has to stay in place/ keep the same structure.

32. anonymous

so you can use 1997 as many times as you want but it keeps that structure, like 1*9*9*7*1*9*9....etc?

33. anonymous

oh... no thats not usable xD

34. anonymous

so you can only use 1997 once then?

35. anonymous

mhmm

36. anonymous

(1 x 9 x 9) + √7 = 214.3

37. anonymous

but wouldn't it be defeating the purpose if you use powers of 3 then? even tho you are multiplying it 3 times... your using a number not in that set..

38. anonymous

probs over thinking it.

39. anonymous

uhhh xD

40. anonymous

I dunno xD Its hard just trying to do it the legit way xD

227 is a prime number, so I suppose the manipulation of the numbers you have should reflect that... I'm struggling quite a bit as well, but maybe you should work backwards? add 1, 9 or 7 to your target number and try to factorize it to get hints on how to create it..

42. anonymous

:o thats a good idea, i'll try that now xD

43. anonymous

I just got 226 :P

44. anonymous

gg no re jade is a genius

45. imqwerty

can we do something like this- $1 \times \sqrt{9},\sqrt[\infty]{9},7 =317$?

46. anonymous

yep

47. imqwerty

so 317 is done :)

48. anonymous

:o thank you xD

49. anonymous

But I don't get how it becomes 317 xD

50. imqwerty

$1 \times \sqrt{9}=1 \times 3=3$$\sqrt[\infty]{9}=1$$7=7$ joining all :) 317

51. anonymous

:o

52. anonymous

thank you for your explanation xD

53. imqwerty

np (:

54. anonymous

and thank you jade, i'll make sure to use your methods :D

@imqwerty You can join the numbers? don't you have to add or multiply?

56. anonymous

OH

57. imqwerty

idk? @Epicteatime said yes so i did it :)

58. anonymous

Yeah, you have to add them or multiply them to get the actual number, sorry Jade I didnt see how you got it xD

59. anonymous

60. anonymous

1×9√,9√∞,7=317

ah, so no joining then, that would have made it easier. :c

62. anonymous

2^2 • 3 • 19 = 228 - (227 +1) 2 • 113 = 226 = (227-1) 22 • 5 • 11 = 220 = (227 - 7) 2 • 32 • 13 = 234 = (227 +7) 22 • 59 = 236 = (227 +9) 2 • 109 = 218 = (227 - 9)

63. anonymous

yeah, it would have

64. anonymous

lauren, thats not how you do it xD Thanks for your effort though :D

I'm sure this is actually a simple question at it's heart, I doubt we need fancy, doctorate level thesis' on how this could work. The numbers we have are 1 , 9 , 9 , 7 , they have to be dealt with in that order, but they can be subtracted and added to each other, as well as divided and multiplied. We can use any number we wish when "doubling" or calculating to the power, right @epicteatime ?

@Epicteatime I got ONE answer. $1 * 9^{2.5} - 9 - 7 = 227$

67. anonymous

sorry, I went to eat dinner xD Im back now tho :D

68. anonymous

and thank you for answering one xD

69. anonymous

sadly there's still like, 4 :P

@Epicteatime Hope you enjoyed dinner haha, I know, but once one goes down, surely the rest should be easier? XD

71. anonymous

maybe, maybe

72. anonymous

xD

73. anonymous

which one are you doing jade?

I'm trying to do the second one now, it's only a difference of 2 so...

75. anonymous

alright, i'll do 271 then :D

76. anonymous

holy crap...

77. anonymous

I Just got 271

78. anonymous

but I still need to do something with 7 xD

So, I need to subtract 14 from $9^{2.5}$ in order to get 229. How can I make 14? --- Also, congrats! I'm sure you can turn the 7 into a 0 somehow...

80. FireKat97

so which ones do you have left? haha

81. anonymous

229 271 317 349

82. anonymous

those :3

83. FireKat97

ahh okiee

84. anonymous

yush :3

85. anonymous

I GOT 271!!!!

86. anonymous

oh wait...

87. anonymous

1997-99-1/7

88. anonymous

uhh

89. anonymous

hmmm....

90. anonymous

1-99/7=271? xD

91. FireKat97

can we use the numbers 1, 9, 9 and 7 as many times as we'd like?

92. anonymous

nope xD

93. anonymous

94. FireKat97

damn ahahha

95. FireKat97

but can we rearrange stuff to make like 99 and 17 and stuff?

96. anonymous

99 yes, 17 no xD

97. anonymous

you have to keep 1997 in that order

98. FireKat97

OH i think I'm finally clear on the rules lololol

99. anonymous

lol xD well try your best :D

100. FireKat97

so slow xD haha, okay

101. anonymous

damn

102. anonymous

I got 318

103. anonymous

.7

104. anonymous

so basically 319 xD

you got 317?

can't you subtract 7^0 to get 317?

107. anonymous

:o

108. anonymous

wait a sec :3

109. anonymous

1 x 9^2.6+9+7

110. anonymous

just putting that there

111. anonymous

I did what you told me jade, and I got 311 xD

whoops haha

113. FireKat97

we can't do 199 + (19 x (9 - 7)) - (7 + 1) = 229 can we? :/

don't think so firekat :c

115. anonymous

ah no xD sorry m80 :P

116. FireKat97

hahah damn

117. FireKat97

btw what year is this? this is torture lol I'd hate getting an assignment like this

118. anonymous

year 10 xD

119. FireKat97

omg seriously, our assignments were so easy in comparison

120. FireKat97

hahahaha we'd get like quadratics 90% of the time

Considering I just started year 11 it is kind of embarrassing I can't solve this lmao

122. FireKat97

lol Im a first year and can't solve it so :\$

but we need to carry on, we can do this!

124. anonymous

YES

125. anonymous

126. FireKat97

HAHAHA

127. anonymous

xD

128. anonymous

I GOT IT

129. anonymous

229!

130. FireKat97

yayayayyayay!!

131. anonymous

1*(99+7^2.5)

132. FireKat97

good job!

133. anonymous

that SHOULD work

134. anonymous

you round it so you get 229

135. FireKat97

but how did you get 2.5?

So you're allowed to combine numbers?

137. anonymous

Yeah, just keep the order

138. anonymous

2.5? its the power

why did i not know this also are you sure you can just round it off?

140. FireKat97

ohh we can use any power?

141. anonymous

pretty sure.

142. anonymous

and yes, you can xD

143. FireKat97

ahhh okayyyy

144. anonymous

you just can't change the number, or change its position

145. FireKat97

ah oka cool

146. anonymous

:3

$1 * (9 - \sqrt9) + 7 ^3 = 349$

148. anonymous

:o

149. anonymous

NICE :D

YAS

151. FireKat97

woww niceee

so 229 271 317 left?

153. anonymous

I got 229

ah okay

155. anonymous

we only got 2 more left

156. anonymous

317 and 349

I got 349 : o

158. anonymous

yep :3

159. anonymous

MVP

160. anonymous

xD

so 271 + 317 ?

162. anonymous

?

163. FireKat97

so if we can use any powers and round off, would $1 \times 9^{5/2} + 9^{3/2} \times 7^{0.026}$ work? cus it gives 271.401..

164. FireKat97

so if we can use any powers and round off, would $1 \times 9^{5/2} + 9^{3/2} \times 7^{0.026}$ work? cus it gives 271.401..

165. anonymous

uhhh... yeah I guess xD

You said we have two left, you solved 229 , and I solved 227 + 349 so the other two are 271 and 317

167. anonymous

ohh thats what you meant xD yes, thats what we have left :D

Very close FireKat! Although I'm wary of decimals, if 2 don't have decimals should others?

169. anonymous

actually its 349 and 317

170. FireKat97

oh

171. anonymous

wait no

$1 * (9 - \sqrt9) + 7^3$ = 349 $1 * 9^{2.5} - 9 - 7$ = 227

173. anonymous

271 and 317

yes

175. anonymous

is what we have left.

176. anonymous

i got 319 again xD

178. anonymous

1x(9^2.5+9)+7

Isn't that 259?

180. anonymous

no idea xD

9^2.5 + 9 + 7 = 259

182. anonymous

damn, got 270, and gg :D

183. anonymous

1+(9.9^3.29)/7

184. anonymous

oh wait I got it

185. anonymous

1+(9.9^3.291)/7 :P

186. anonymous

271.1

187. anonymous

now we only have 317

very close

Unfortunately I can't stay any more, I have a lot of work myself. :c Please message me with your results. ;u;

190. anonymous

lol alright xD Thanks a lot for your help fwendo :D

191. anonymous

gg done :D Thanks everyone for participating :D