Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

What is the question?

You have to make those numbers by using 1997

I can't get it at all, so I was wondering if anyone else could help me with this xD

interesting :)

Can't do it xD

Closest I got was 220

can we rearrange the number 1,9,9,7?

nope xD

it has to stay in that specific order

(1 + 9) x 9 x √7 = 238.1

SO CLOSE

this is hard, how did you get 220?

(19+9)+7^2

(1 + √9) x 9 x 7 = 252

(19 x 9) + 7^2 = 220

yep, thats what I did xD

closest thing I got xD

(1 x 9 x 9) + √7 = 214.3

:o

\[\sqrt{\sqrt{1\times 9^9\times7}}=228.2\]

wow, thats really close /:

So annoying... this stupid assignment.

can you use powers of numbers other than 1,9,9,7?

if you mean, can you square it or "double it" yes you can

but 1997 has to stay in place/ keep the same structure.

oh... no thats not usable xD

so you can only use 1997 once then?

mhmm

(1 x 9 x 9) + √7 = 214.3

probs over thinking it.

uhhh xD

I dunno xD Its hard just trying to do it the legit way xD

:o thats a good idea, i'll try that now xD

I just got 226 :P

gg no re jade is a genius

can we do something like this-
\[1 \times \sqrt{9},\sqrt[\infty]{9},7 =317\]?

yep

so 317 is done :)

:o thank you xD

But I don't get how it becomes 317 xD

\[1 \times \sqrt{9}=1 \times 3=3\]\[\sqrt[\infty]{9}=1\]\[7=7\]
joining all :)
317

:o

thank you for your explanation xD

np (:

and thank you jade, i'll make sure to use your methods :D

OH

idk? @Epicteatime said yes so i did it :)

not jade, imqwerty

1×9√,9√∞,7=317

ah, so no joining then, that would have made it easier. :c

yeah, it would have

lauren, thats not how you do it xD Thanks for your effort though :D

@Epicteatime
I got ONE answer.
\[1 * 9^{2.5} - 9 - 7 = 227 \]

sorry, I went to eat dinner xD Im back now tho :D

and thank you for answering one xD

sadly there's still like, 4 :P

maybe, maybe

xD

which one are you doing jade?

I'm trying to do the second one now, it's only a difference of 2 so...

alright, i'll do 271 then :D

holy crap...

I Just got 271

but I still need to do something with 7 xD

so which ones do you have left? haha

229
271
317
349

those :3

ahh okiee

yush :3

I GOT 271!!!!

oh wait...

1997-99-1/7

uhh

hmmm....

1-99/7=271? xD

can we use the numbers 1, 9, 9 and 7 as many times as we'd like?

nope xD

sadly xD

damn ahahha

but can we rearrange stuff to make like 99 and 17 and stuff?

99 yes, 17 no xD

you have to keep 1997 in that order

OH i think I'm finally clear on the rules lololol

lol xD well try your best :D

so slow xD haha, okay

damn

I got 318

.7

so basically 319 xD

you got 317?

can't you subtract 7^0 to get 317?

:o

wait a sec :3

1 x 9^2.6+9+7

just putting that there

I did what you told me jade, and I got 311 xD

whoops haha

we can't do 199 + (19 x (9 - 7)) - (7 + 1) = 229 can we? :/

don't think so firekat :c

ah no xD sorry m80 :P

hahah damn

btw what year is this? this is torture lol I'd hate getting an assignment like this

year 10 xD

omg seriously, our assignments were so easy in comparison

hahahaha we'd get like quadratics 90% of the time

Considering I just started year 11 it is kind of embarrassing I can't solve this lmao

lol Im a first year and can't solve it so :$

but we need to carry on, we can do this!

YES

BELIEVE IN YOUR DREAMS!

HAHAHA

xD

I GOT IT

229!

yayayayyayay!!

1*(99+7^2.5)

good job!

that SHOULD work

you round it so you get 229

but how did you get 2.5?

So you're allowed to combine numbers?

Yeah, just keep the order

2.5? its the power

why did i not know this
also are you sure you can just round it off?

ohh we can use any power?

pretty sure.

and yes, you can xD

ahhh okayyyy

you just can't change the number, or change its position

ah oka cool

:3

\[1 * (9 - \sqrt9) + 7 ^3 = 349\]

:o

NICE :D

YAS

woww niceee

so
229
271
317
left?

I got 229

ah okay

we only got 2 more left

317 and 349

I got 349 : o

yep :3

MVP

xD

so 271 + 317 ?

uhhh... yeah I guess xD

You said we have two left,
you solved 229 , and I solved 227 + 349 so the other two are 271 and 317

ohh thats what you meant xD yes, thats what we have left :D

Very close FireKat!
Although I'm wary of decimals, if 2 don't have decimals should others?

actually its 349 and 317

oh

wait no

\[1 * (9 - \sqrt9) + 7^3 \] = 349
\[1 * 9^{2.5} - 9 - 7\] = 227

271 and 317

yes

is what we have left.

i got 319 again xD

What is your equation?

1x(9^2.5+9)+7

Isn't that 259?

no idea xD

9^2.5 + 9 + 7 = 259

damn, got 270, and gg :D

1+(9.9^3.29)/7

oh wait I got it

1+(9.9^3.291)/7 :P

271.1

now we only have 317

very close

lol alright xD Thanks a lot for your help fwendo :D

gg done :D Thanks everyone for participating :D