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anonymous
 one year ago
Stuck on some simple algebra in the very first example of the first lecture (talk about rusty!).
I understand the algebra all the way until the end where:
(1/Δx)[(x0(x0+Δx))/((x0+Δx)x0)] =
(1/Δx)[(Δx/((x0+Δx)x0)]
How does the numerator reduce to Δx?
Wouldn't x0(x0+Δx) = Δx?
anonymous
 one year ago
Stuck on some simple algebra in the very first example of the first lecture (talk about rusty!). I understand the algebra all the way until the end where: (1/Δx)[(x0(x0+Δx))/((x0+Δx)x0)] = (1/Δx)[(Δx/((x0+Δx)x0)] How does the numerator reduce to Δx? Wouldn't x0(x0+Δx) = Δx?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0After some thought, I believe I answered my own question. The minus sign is transitive and is reduced to x0  x0  Δx.

phi
 one year ago
Best ResponseYou've already chosen the best response.1you "distribute" the minus sign 1*(a +b) = 1*a + 1*b = a  b
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