If a nine-digit number \(x\) is formed using 1, 2, 3, 4, 5, 6, 7, 8, 9 without repetition, then find the probability that the non-negative difference among all the digits equidistant from both ends is 1.

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How does this work?
864,152,579 is one such number.
But 5 is equidistant to both ends and 5-5=0.

Nah, the number at the center is not considered, because that way, there would be no such number.

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