Research building codes for ramps such as wheelchair ramps, boat ramps, or loading docks. Choose a building code for a ramp and describe the relationship between the lengths involved using geometry vocabulary such as hypotenuse, adjacent side, and opposite side. Use right triangle concepts from this unit to find any unknown lengths and angle measures of the ramp. Be sure to identify the type of ramp. Discuss why there are building codes for ramps and how you think they are determined.

- anonymous

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- sleepyjess

First off, lets break this into parts.
Research building codes for ramps such as wheelchair ramps, boat ramps, or loading docks.

- sleepyjess

Which one of those ramps would you like to research?

- anonymous

I have the codes for wheel chair ramps.
Wheelchair ramps: The ramp should be no steeper than one foot per inch of rise, rise should not exceed 30 inches, width must be at least 36 inches, and landings much be at least 60 square inches both at the top of the platform and in any directional transition. Handrails are required on ramps that rise more than 6 inches or any more than 72 inches long. Wheelchair ramps may be fabricated from any material, provided they do not allow water to accumulate and have enough tread to prevent slipping.

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## More answers

- sleepyjess

Awesome! So the entire ramp should not be over 30 inches high. |dw:1444310730469:dw|

- sleepyjess

How much do you think our rise should be?

- anonymous

If its 1 ft per inch of rise, it could be 30 ft.

- sleepyjess

So you want the height to be 30 inches?

- anonymous

I think lol

- sleepyjess

Okay, so the height is 30 inches, and they have to have AT LEAST one foot of length per inch of height, which means at a minimum, we have a 30ft long ramp

- sleepyjess

|dw:1444311099329:dw|

- anonymous

so since I have those two values, couldn't I solve to find the other value?

- sleepyjess

Exactly!

- sleepyjess

Do you know how to use sin, cos and tan?

- anonymous

Yes I do, thank you so so sooooo much!

- sleepyjess

No problem! Let me know what you come to as an answer for the hypotenuse :)

- anonymous

But I need an angle value...

- anonymous

I know since I have the adjacent and opposite sides I would use tan

- sleepyjess

Well, we know that opposite is 30 inches, and adjacent is 360 inches (30ft *12 inches). So what operation (sin, cos, tan) would we use to find angle A?|dw:1444311592484:dw|

- sleepyjess

Yep, you're already ahead of me :)

- sleepyjess

Do you know how to use inverse tan?

- anonymous

No, I don't

- sleepyjess

Let me refresh on this really quickly

- sleepyjess

Or call @freckles over because I'm confusing myself...

- anonymous

If I did this right it think it would be 85.2

- sleepyjess

That sounds a lot more reasonable than what I'm getting...

- anonymous

so if that's the measure of the angle, how would I go about solving it to find the hypotenuse? I've only dealt with one value being x when working with sin, cos, and tan.

- sleepyjess

Okay, you have angle B, with that we can find angle A (4.8)
|dw:1444312183349:dw|

- sleepyjess

We have theta now, so we can plug that in, \(\tan(85.2)=\dfrac{30}{360}\)

- sleepyjess

Wait

- anonymous

wouldn't I plug in 4.8

- sleepyjess

yes yes yes, you can use sin(4.8)=x/30 or cos(4.8)x/360

- sleepyjess

cos(4.8)=x/360

- anonymous

\[\tan 4.8=30/360\]

- anonymous

Okay thank you so very much!

- sleepyjess

No problem! Thank you for refreshing my memory on sin, cos and tan :)

- anonymous

So I used cos and when I worked it out I got 368.56 would that be right?

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