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- anonymous

Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = -0.005x2 + 0.41x - 5.1, where x is the horizontal distance of the rock, in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizontally from Landon will the rock land?

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- Theloshua

\[y = -0.005x^{2} + 0.41x - 5.1\]

- Theloshua

is that the equation?

- mathstudent55

You are looking for distance a.
|dw:1444311498356:dw|

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- mathstudent55

|dw:1444311669302:dw|

- mathstudent55

The place where the rock lands is at ground level.
Notice that the variable y has been defined as the height of the rock, in feet, above ground level.

- mathstudent55

What is y where the rock lands?

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