(4,1); perpendicular to y=1/3x+3. How to solve it?

- Epicteatime

(4,1); perpendicular to y=1/3x+3. How to solve it?

- katieb

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- Epicteatime

- Epicteatime

- Epicteatime

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## More answers

- ganeshie8

What exactly are you trying to solve here ?

- Epicteatime

I want to know the method to solve the problem

- Epicteatime

I need to use like y-y1=m(x-x1)

- Epicteatime

to find the equation

- ganeshie8

that's fine,
may i know what equation you're trying to find ?

- ganeshie8

the problem is not clear to me yet..

- Jadedry

@Epicteatime
Hi again!
I too am a bit confused as to what you are trying to find. :c

- Epicteatime

the equation for the line that passes through the given point and satisfies the given condition. And Hi jade :3

- Epicteatime

Like, do I use the opposite slope? -3/1 since its perpendicular?

- Jadedry

So the line has to be perpendicular to y = 1 and it has to pass through the point 4,1 ?

- Epicteatime

yes, basically

- anonymous

you have an X and the Y just plug in the numbers and then get the answer of Y = 1/15

- Jadedry

Then the equation for the line should be x = 4
It would be perpendicular to you, which is a horizontal line, and it would pass through 4,1

- Jadedry

Unless there is another piece of info I should take into account?

- Epicteatime

hmmm

- Epicteatime

like if it was parallel, I could have used the slope from the line stuff that is given.

- Jadedry

Wait, Is the equation for Y
\[y = \frac{ 1 }{ 3x+3 }\] ?

- Epicteatime

uhh, I have no idea xD Thats why I'm here xD

- Jadedry

Your textbook should tell you though, the format in which you wrote it was a bit confusing, I thought y=1 at first?

- Epicteatime

hmm, maybe maybe xD

- Epicteatime

its ok, i'll ask my teacher/ look at my textbooks :3 gnat :D

- Epicteatime

*gnyt

- Jadedry

Ah, okay. Good night! c:

- anonymous

Y does equal 1 it says so in the point for the graph( 4,1)

- Epicteatime

yep, completely :D

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