## anonymous one year ago (4,1); perpendicular to y=1/3x+3. How to solve it?

1. anonymous

2. anonymous

@Hero @ganeshie8

3. anonymous

@ParthKohli @mathstudent55

4. ganeshie8

What exactly are you trying to solve here ?

5. anonymous

I want to know the method to solve the problem

6. anonymous

I need to use like y-y1=m(x-x1)

7. anonymous

to find the equation

8. ganeshie8

that's fine, may i know what equation you're trying to find ?

9. ganeshie8

the problem is not clear to me yet..

@Epicteatime Hi again! I too am a bit confused as to what you are trying to find. :c

11. anonymous

the equation for the line that passes through the given point and satisfies the given condition. And Hi jade :3

12. anonymous

Like, do I use the opposite slope? -3/1 since its perpendicular?

So the line has to be perpendicular to y = 1 and it has to pass through the point 4,1 ?

14. anonymous

yes, basically

15. anonymous

you have an X and the Y just plug in the numbers and then get the answer of Y = 1/15

Then the equation for the line should be x = 4 It would be perpendicular to you, which is a horizontal line, and it would pass through 4,1

Unless there is another piece of info I should take into account?

18. anonymous

hmmm

19. anonymous

like if it was parallel, I could have used the slope from the line stuff that is given.

Wait, Is the equation for Y $y = \frac{ 1 }{ 3x+3 }$ ?

21. anonymous

uhh, I have no idea xD Thats why I'm here xD

Your textbook should tell you though, the format in which you wrote it was a bit confusing, I thought y=1 at first?

23. anonymous

hmm, maybe maybe xD

24. anonymous

its ok, i'll ask my teacher/ look at my textbooks :3 gnat :D

25. anonymous

*gnyt

Ah, okay. Good night! c:

27. anonymous

Y does equal 1 it says so in the point for the graph( 4,1)

28. anonymous

yep, completely :D