adll23
  • adll23
The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units? (4 points) No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64 No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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narutoboy14
  • narutoboy14
d
mathstudent55
  • mathstudent55
What is the perimeter of a rectangle?
adll23
  • adll23
2 (w + h)

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More answers

mathstudent55
  • mathstudent55
Great. The problem is calling the length x and the width y. According to the variables of the problem, then, the perimeter is P = 2(x + y) Ok?
mathstudent55
  • mathstudent55
We are told the length is 20 and the width is 11. What would the perimeter be? P = 2(x + y) P = 2(20 + 11) P = 2(31) P = 62 With the length 20 and width 11, the perimeter is 62, not 64. This means the perimeter cannot be 64.
mathstudent55
  • mathstudent55
Notice that when you calculate the perimeter, you add the length and width, and then you multiply that by 2. That means the length + the width must equal half the perimeter. In our case, the length + the width = 20 + 11 = 31 Since we are told the perimeter is 64, half the perimeter is 32. 31 is not half the perimeter, so 64 cannot be the perimeter.
adll23
  • adll23
So it would be B?
adll23
  • adll23
@mathstudent55
adll23
  • adll23
Or would it be A? @mathstudent55
narutoboy14
  • narutoboy14
b
mathstudent55
  • mathstudent55
The answer is B.

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