anonymous
  • anonymous
What is the equation of the graphed line? Hint: Determine the slope of the line. y = x Graph of a line passing through the origin and Quadrants II and IV. Line passes through (1, -5).
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
https://static.k12.com/calms_media/media/1503000_1503500/1503205/3/0539777c91888fdb4df047b53ea5acb32adf5549/MS_IMC-140516-1000015.jpg graph to the question
texaschic101
  • texaschic101
lets find the slope by using the slope formula and 2 sets of points. slope(m) = (y2 - y1) / (x2 - x1) (0,0)...x1 = 0 and y1 = 0 (1,-5)...x2 = 1 and y2 = -5 now we sub slope(m) = (-5 - 0) / (1 - 0) slope(m) = -5/1 or just -5 now we use y = mx + b slope(m) = -5 use either of your points...(1,-5)...x = 1 and y = -5 now we sub and find b, the y intercept -5 = -5(1) + b -5 = -5 + b -5 + 5 = b 0 = b so the equation of the line is : y = -5x + 0...or just y = -5x

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