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anonymous

  • one year ago

Help please. Fan and medal https://gyazo.com/92da426c34fb191385e39440c5bb60c8

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  1. anonymous
    • one year ago
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    @Jack1

  2. anonymous
    • one year ago
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    @HelloKitty17

  3. anonymous
    • one year ago
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    Hey can you help me please

  4. Jack1
    • one year ago
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    yep, was jus lookin a t the equation, do u know how to solve?

  5. anonymous
    • one year ago
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    No :|

  6. Jack1
    • one year ago
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    ok, consider the equals sing like a seesaw, so if u do something to the numbers on one side of it, u have to do the same thing to the numbers on the other side so lets solve together and see how many solutions, yeah?

  7. Jack1
    • one year ago
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    *equals sign... damn my clumsy fingers, sorry :(

  8. anonymous
    • one year ago
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    Oh yeah lol

  9. Jack1
    • one year ago
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    4(2x +3) = 2(3x -4) this is ur equation, right?

  10. anonymous
    • one year ago
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    Yes

  11. Jack1
    • one year ago
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    cool, so first, expand out the brackets \(\large 4(2x +3) = 2(3x -4)\) \(\large 4 \times 2x + 4 \times 3 = 2 \times 3x - 2 \times 4\) \(\large 8x + 12 = 6x - 8\) ... right?

  12. anonymous
    • one year ago
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    Right

  13. Jack1
    • one year ago
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    cool, so now combine like terms \(\large 8x + 12 = 6x - 8\) so subtract 6x from both sides of the equation \(\large 8x + 12 -6x = 6x - 8 -6x\) \(\large 2x + 12 = - 8\) k now u: subtract 12 from both sides of the equation please

  14. anonymous
    • one year ago
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    Um subtract 12 from what side :/

  15. Jack1
    • one year ago
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    from both sides of the equals sign eg 2x + 12 = -8 2x + 12 -12 = -8 -12

  16. anonymous
    • one year ago
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    -20

  17. anonymous
    • one year ago
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    -8

  18. Jack1
    • one year ago
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    yep, exactly: 2x = -20 so x = ...?

  19. anonymous
    • one year ago
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    -20

  20. Jack1
    • one year ago
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    ...no 2x = -20 so x = -20/2 = -10... yeah?

  21. anonymous
    • one year ago
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    Ohh that's a division sign didn't see it sorry lol

  22. anonymous
    • one year ago
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    right

  23. Jack1
    • one year ago
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    all good ;) so yeah, it has a solution, we solved it, and there's no plus or minus there so it's just the 1 solution...

  24. anonymous
    • one year ago
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    Okay is it fine if you help me with more?

  25. Jack1
    • one year ago
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    sure, just shut down this thread tho and open a new one as the equations tend to slow things down a bit plz ;)

  26. anonymous
    • one year ago
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    Okay

  27. anonymous
    • one year ago
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    Do we still work in this one?

  28. Jack1
    • one year ago
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    no, just hit the close question button, and open a new one and tag me in it and i'll be there quick as (:

  29. anonymous
    • one year ago
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    okay!!

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spraguer (Moderator)
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