anonymous
  • anonymous
Help please. Fan and medal https://gyazo.com/92da426c34fb191385e39440c5bb60c8
Mathematics
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anonymous
  • anonymous
Help please. Fan and medal https://gyazo.com/92da426c34fb191385e39440c5bb60c8
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
Hey can you help me please

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Jack1
  • Jack1
yep, was jus lookin a t the equation, do u know how to solve?
anonymous
  • anonymous
No :|
Jack1
  • Jack1
ok, consider the equals sing like a seesaw, so if u do something to the numbers on one side of it, u have to do the same thing to the numbers on the other side so lets solve together and see how many solutions, yeah?
Jack1
  • Jack1
*equals sign... damn my clumsy fingers, sorry :(
anonymous
  • anonymous
Oh yeah lol
Jack1
  • Jack1
4(2x +3) = 2(3x -4) this is ur equation, right?
anonymous
  • anonymous
Yes
Jack1
  • Jack1
cool, so first, expand out the brackets \(\large 4(2x +3) = 2(3x -4)\) \(\large 4 \times 2x + 4 \times 3 = 2 \times 3x - 2 \times 4\) \(\large 8x + 12 = 6x - 8\) ... right?
anonymous
  • anonymous
Right
Jack1
  • Jack1
cool, so now combine like terms \(\large 8x + 12 = 6x - 8\) so subtract 6x from both sides of the equation \(\large 8x + 12 -6x = 6x - 8 -6x\) \(\large 2x + 12 = - 8\) k now u: subtract 12 from both sides of the equation please
anonymous
  • anonymous
Um subtract 12 from what side :/
Jack1
  • Jack1
from both sides of the equals sign eg 2x + 12 = -8 2x + 12 -12 = -8 -12
anonymous
  • anonymous
-20
anonymous
  • anonymous
-8
Jack1
  • Jack1
yep, exactly: 2x = -20 so x = ...?
anonymous
  • anonymous
-20
Jack1
  • Jack1
...no 2x = -20 so x = -20/2 = -10... yeah?
anonymous
  • anonymous
Ohh that's a division sign didn't see it sorry lol
anonymous
  • anonymous
right
Jack1
  • Jack1
all good ;) so yeah, it has a solution, we solved it, and there's no plus or minus there so it's just the 1 solution...
anonymous
  • anonymous
Okay is it fine if you help me with more?
Jack1
  • Jack1
sure, just shut down this thread tho and open a new one as the equations tend to slow things down a bit plz ;)
anonymous
  • anonymous
Okay
anonymous
  • anonymous
Do we still work in this one?
Jack1
  • Jack1
no, just hit the close question button, and open a new one and tag me in it and i'll be there quick as (:
anonymous
  • anonymous
okay!!

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